Warning: Speculative material under construction.
The following material began as a post on the nCafe…
Given a manifold and differential forms on , we can construct a simplicial complex with cochains . The de Rham map takes forms on and turns them into cochains on
The Whitney map () takes cochains on and turns them into (Whitney) forms on
We have
and
The wedge product in is graded commutative and the cup product in is not graded commutative “on the nose” so all these maps do not quite fit together perfectly, e.g.
and
Some people have proposed a modified cup product for computational physics via
I don’t think this helps much with the “cochain problem”. In particular, this modified cup product is not even associative!
I have proposed an alternative, which at first will seem radical but I actually think might help with things like the “cochain problem”. That is to introduce a modified wedge product
This modified wedge product has the (uber) nice property that it is an algebra homomorphism “on the nose”, i.e.
The undesirable property of this modified wedge product is that it will depend on triangulation , but that dependence disappears when you pass to cohomology, homotopy, etc, which is what the mathematicians really care about.
My gut tells me that having a true algebra morphism like this will give you true functors and the category theoretic analysis will be much cleaner. But that is just a hunch.
Also note that in a suitable limit of refinements of S, i.e. a kind of “continuum limit” we have
Both the Whitney map and de Rham map preserve unit elements, i.e.
and
Given a differential form , let denote the corresponding Whitney form given by
The Whitney form may be thought of as a piecewise linear approximation to the smooth differential form .
The map
is a projection from smooth forms to Whitney forms, which can be seen by expanding
and noting that so that
Now, I have proposed above using this modified wedge product on smooth forms, but that might not be the right thing to do. For example, consider the modified wedge product of a smooth form and the unit 0-form 1
However,
Therefore, what I have really done is define an algebra of Whitney forms.
This is significant because Whitney forms are not closed under the ordinary wedge product, i.e.
is not a Whitney form (which always bugged me). However
is a Whitney form.
The exterior derivative behaves nicely with respect to both the Whitney and de Rham maps, i.e.
and
In particular, this means that
so the exterior derivative of a Whitney form is a Whitney form.
For smooth forms and , we have the Leibniz rule
For cochains and , we have the Leibniz rule
The Leibniz rule is important for many reasons, not least of them being that it preserves cohomological properties.
Therefore, it is important to note that Whitney forms together with the modified wedge product also satisfy the Leibniz rule
All this taken together means that on a manifold we have a full fledged graded differential algebra of Whitney forms
where is the space of Whitney -forms on . We have an exterior derivative
that is nilpotent () and satisfies the graded Leibniz rule
However, the modified wedge product of Whitney forms is not graded commutative, i.e.
This failure to be graded commutative is a feature (and not a bug that) leads to all kinds of fascinating concepts related to, among other things, quantum mechanics and noncommutative geometry.
To be continued…