Eric Forgy Noncommutative Stochastic Calculus

Given any first order calculus (d,Ω 1(A))(d,\Omega^1(A)) on a commutative algebra AA, we have

d(fg)=d(gf)⇒[df,g]=[dg,f].d(f g) = d(g f)\implies [d f,g] = [d g,f].

According to

this is enough to show that the commutator is a symmetric AA-bilinear function of dfd f and dgd g, i.e.

[df,g]=C(df,dg).[d f,g] = C(d f,d g).

The symmetric AA-bilinear map CC extends to a product

C:Ω 1(A)×Ω 1(A)→Ω 1(A),C:\Omega^1(A)\times\Omega^1(A)\to\Omega^1(A),

since Ω 1(A)\Omega^1(A) is generated by elements of the form a(db)a(d b) for a,b∈Aa,b\in A. We will denote this product

α•β≔C(α,β).\alpha\bullet\beta \coloneqq C(\alpha,\beta).

This allows us to write the product rule in “left component form” as

d(fg)=f(dg)+g(df)+df•dg,d(f g) = f(d g) + g(d f) + d f\bullet d g,

in “right component form” as

d(fg)=(dg)f+(df)g−df•dg,d(f g) = (d g)f + (d f)g - d f\bullet d g,

or the “symmetrized form” as

d(fg)=12[f(dg)+(dg)f]+12[g(df)+(df)g].d(f g) = \frac{1}{2}\left[f(d g) + (d g)f\right] + \frac{1}{2}\left[g(d f) + (d f)g\right].
Created on January 4, 2010 at 15:23:35 by Eric Forgy