A monomorphism in a derivator is the generalization to the context of a derivator of the notion of monomorphism in ordinary category theory. Viewing a derivator as the “shadow” of an (∞,1)-category, the notion of monomorphism therein coincides with the notion of monomorphism in an (∞,1)-category.

Definition

Let $\square$ denote the category

$\array{a & \to & b \\ \downarrow & & \downarrow \\ c & \to & d}$

that is the “free-living commutative square”, let $I$ be the interval category$(0\to 1)$, and let $p\colon \square \to I$ denote the functor collapsing $a,b,c$ to $0$ and sending $d$ to $1$.

Let $D$ be a prederivator and $f\colon X\to Y$ a morphism in $D(1)$. By one of the axioms of a derivator, there exists an object $F\in D(I)$ representing $f$, which is unique up to non-unique isomorphism. We say that $f$ is a monomorphism in $D$ if $p^*(F) \in D(\square)$ is a pullback square.

Examples

It is well-known and easy to verify that a morphism $f:A\to B$ in a 1-category is a monomorphism if and only if the square

$\array{ A & \overset{id}{\to} & A \\ ^{id}\downarrow & & \downarrow^f \\ A &\underset{f}{\to} & B }$

is a pullback. Therefore, in representable prederivators this definition reduces to the usual notion of monomorphism.

In the homotopy derivator of an $(\infty,1)$-category, one can check that this reduces to the usual notion of monomorphism in an (∞,1)-category.

Created on June 12, 2010 at 04:44:22.
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