nLab residuated idempotent semiring

Contents

Idea

In general, in the idempotent semiring (max,+)(max,+), an equation of form Ax=bA x = b has no solution, but the inequality AxbA x \leq b does by taking x=𝟘x=\mathbb{0}. (Here recall that in any idempotent semiring, there is a natural partial order on its elements.) It is natural to relax equality in the search for solutions, and study instead the set of its ‘subsolutions’. One way forward in this approach is to use the notion of residuated mapping from the theory of posets.

Definition

An idempotent semiring, SS is residuated if the right and left multiplication maps

λ a:xax \lambda_a \colon x\mapsto a x

and

ρ a:xxa \rho_a \colon x\mapsto x a

from SS to itself are residuated.

Example

Any complete idempotent semiring is automatically residuated. We set

a\bλ a #(b)=max{xaxb} a \backslash b \coloneqq \lambda^\#_a (b) = max \{x \mid a x \leq b\}

and

b/aρ a #(b)=max{xxab}. b / a \coloneqq \rho_a^\# (b) = max \{ x \mid x a \leq b\} \,.

In the completed (max,+)(max,+) semiring, ¯ max\overline{\mathbb{R}}_{max}, a\ba\backslash b and b/ab/a are equal and both equal bab-a, provided that a𝟘a\neq \mathbb{0}, in which case they equal ++\infty.

References

Last revised on June 13, 2025 at 08:22:09. See the history of this page for a list of all contributions to it.