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\begin{document}

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\section*{Ore localization}

\hypertarget{contents}{}\section*{{Contents}}\label{contents}

\noindent\hyperlink{definition}{Definition}\dotfill \pageref*{definition} \linebreak
\noindent\hyperlink{related_concepts}{Related concepts}\dotfill \pageref*{related_concepts} \linebreak
\noindent\hyperlink{references}{References}\dotfill \pageref*{references} \linebreak


\hypertarget{definition}{}\subsection*{{Definition}}\label{definition}

If $S\subset R$ is a left [[Ore set]] in a monoid (or a ring) $R$, then we call the pair $(j,S^{-1}R)$ where $j:R\to S^{-1}R$ is a morphism of monoids (rings) the \textbf{left Ore localization} of $R$ with respect to $S$ if it is the universal object in the category $C = C(R,S)$ whose objects are the pairs $(f,Y)$ where $f : R \rightarrow Y$ is a morphism of rings from $R$ into a ring $Y$ such that the image $f(S)$ of $S$ consists of units (=multiplicatively invertible elements), and the morphisms $\alpha : (f,Y) \rightarrow (f',Y')$ are maps of rings $\alpha : Y \rightarrow Y'$ such that $\alpha \circ f = f'$.

The definition of $C$ makes sense even if $S\subset R$ is not left Ore; the universal object in $C$ may then exist when $S$ is not left Ore, for example this is the case when $S$ is right Ore, while not left Ore. In fact, the universal object is a left Ore localization (i.e. $S$ is left Ore) iff it lies in the full subcategory $C^l$ of $C$ whose objects $(f,Y)$ satisfy two additional conditions:

(i) $f(S)^{-1}f(R) = \{(f(s))^{-1}f(r)\,|\, s \in S, r\in R\}$ is a subring in $Y$,

(ii) $ker\,f = I_S$.

Hence $(j,S^{-1}R)$ is universal in $C^l$, and that characterizes it, but the universality in $C$, although not characteristic, appears to be more useful in practice.

For every left Ore set $S\subset R$ in a monoid or ring $R$, the left Ore localization exists and it can be defined as follows. As a set, $S^{-1}R := S\times R/\sim$, where $\sim$ is the following relation of equivalence:

\begin{displaymath}
(s,r) \sim (s',r') \,\,\Leftrightarrow\,\,
(\exists \tilde s\in S \,\,\exists \tilde{r}\in R) \,\,
(\tilde{s}s' = \tilde{r}s\,\,and\,\,\tilde{s}r' = \tilde{r}r).
\end{displaymath}
A class of equivalence of $(s,r)$ is denoted $s^{-1}r$ and called a left fraction. The multiplication is defined by $s_1^{-1}r_1\cdot s_2^{-1}r_2 = (\tilde{s}s_1)^{-1} (\tilde{r}r_2)$ where $\tilde{r} \in R, \tilde{s} \in S$ satisfy $\tilde{r}s_2 = \tilde{s}r_1$ (one should think of this, though it is not yet formally justified at this point, as $s^{-1}\tilde{r} = r_1 s_2^{-1}$, what enables to put inverses one next to another and then the multiplication rule is obvious). If the monoid $R$ is a ring then we can extend the addition to $S^{-1}R$ too. Suppose we are given two fractions with representatives $(s_1,r_1)$ and $(s_2,r_2)$. Then by the left Ore condition we find $\tilde{s} \in S$, $\tilde{r}\in R$ such that $\tilde{s} s_1 = \tilde{r} s_2$. The sum is then defined

\begin{displaymath}
s_1^{-1} r_1 + s_2^{-1} r_2 \,:=\,
 (\tilde{s}s_1)^{-1} (\tilde{s}r_1 + \tilde{r}r_2)
\end{displaymath}
It is a long and at points tricky to work out all the details of this definition. One has to show that $\sim$ is indeed relation of equivalence, that the operations are well defined, and that $S^{-1}R$ is indeed a ring. Even the commutativity of the addition needs work (there is an alternative definition of addition in which $\tilde{s}$ above is not required to be in $S$ but the product $\tilde{s}r_1$ is in $S$; this approach is manifestly commutative but it has some other drawbacks). At the end, one shows that the map $j = j_S : R \rightarrow S^{-1}R$ given by $i(r) = 1^{-1}r$ is a homomorphism of rings, which is 1-1 iff the 2-sided ideal $I_S = \{ n \in R \,|\,\exists s \in S,\, sn = 0\}$ is zero.

Basic property of Ore localization is flatness: $S^{-1}R$ is flat $R$-bimodule. The left Ore localization $j : R\to S^{-1}R$ induced a flat localization functor for the category of left $R$-modules or the category of right $R$-modules. The localization functor is the extension of scalars along $l_S: R\to S^{-1}R$, that is (in the case of left $R$-modules) $M\mapsto S^{-1}R\otimes_R M$ is the flat localization functor $Q^*_S:{}_R Mod\to {}_{S^{-1}R}Mod$ and the restriction of scalars is its right adjoint $Q_{S*}$ which is fully faithful and it has its own right adjoint (the localization functor is affine).

\hypertarget{related_concepts}{}\subsection*{{Related concepts}}\label{related_concepts}

\begin{itemize}%
\item [[Ore domain]]

\end{itemize}
\hypertarget{references}{}\subsection*{{References}}\label{references}

\begin{itemize}%
\item K. R. Goodearl, Robert B. Warfield, \emph{An introduction to noncommutative Noetherian rings}, London Math. Soc. Student Texts \textbf{16} (1st ed,), 1989, xviii+303 pp.; or \textbf{61} (2nd ed.), 2004, xxiv+344 pp.


\item [[Zoran Škoda]], \emph{Noncommutative localization in noncommutative geometry}, London Math. Society Lecture Note Series 330 (\href{http://www.maths.ed.ac.uk/~aar/books/nlat.pdf}{pdf}), ed. A. Ranicki; pp. 220--313, \href{http://arxiv.org/abs/math.QA/0403276}{math.QA/0403276}.



\end{itemize}
[[!redirects Ore localizations]]



\end{document}