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\newtheorem{prop}{Proposition} \newtheorem{cor}{Corollary} \newtheorem*{utheorem}{Theorem} \newtheorem*{ulemma}{Lemma} \newtheorem*{uprop}{Proposition} \newtheorem*{ucor}{Corollary} \theoremstyle{definition} \newtheorem{defn}{Definition} \newtheorem{example}{Example} \newtheorem*{udefn}{Definition} \newtheorem*{uexample}{Example} \theoremstyle{remark} \newtheorem{remark}{Remark} \newtheorem{note}{Note} \newtheorem*{uremark}{Remark} \newtheorem*{unote}{Note} %------------------------------------------------------------------- \begin{document} %------------------------------------------------------------------- \section*{topological field} \hypertarget{contents}{}\section*{{Contents}}\label{contents} \noindent\hyperlink{idea}{Idea}\dotfill \pageref*{idea} \linebreak \noindent\hyperlink{definition}{Definition}\dotfill \pageref*{definition} \linebreak \noindent\hyperlink{internalization}{Internalization}\dotfill \pageref*{internalization} \linebreak \noindent\hyperlink{classical_internalization}{``Classical'' internalization}\dotfill \pageref*{classical_internalization} \linebreak \noindent\hyperlink{examples}{Examples}\dotfill \pageref*{examples} \linebreak \hypertarget{idea}{}\subsection*{{Idea}}\label{idea} A topological field is a [[field]] equipped with a topology such that all of the field operations are [[continuous functions]]. \hypertarget{definition}{}\subsection*{{Definition}}\label{definition} A \emph{topological field} is a [[topological ring]] whose underlying [[ring]] in $Set$ is a [[field]] $K$ and such that the multiplicative inversion operation $i: K \setminus \{0\} \to K \setminus \{0\}$ is [[continuous function|continuous]] with respect to the [[subspace]] topology inherited from $K$. \begin{remark} \label{}\hypertarget{}{} Note it is not automatic that inversion is continuous for a field equipped with a ring topology (when it is, we say the ring topology is a \emph{field topology}). The following gives an example of a ring topology that is not a field topology: on the [[rational numbers]] $\mathbb{Q}$, take the set of [[ideals]] $n\mathbb{Z}$, $0 \neq n \in \mathbb{Z}$, to be a filter base for a [[filter]] of [[neighborhoods]] of $0$. That this gives a ring topology follows from three easily verified facts: (1) for any ideal $I$ there is an ideal $J$ such that $J + J \subseteq I$ and $-J \subseteq I$ (e.g., $J = I$), (2) if $I$ is any ideal and $q \in \mathbb{Q}$ is any element, there is an ideal $J$ such that $q J \subseteq I$, and (3) if $I$ is any ideal, there is an ideal $J$ such that $J J \subseteq I$ (again take $J = I$). It's easy to see that this ring topology is [[Hausdorff space|Hausdorff]]. But inversion on the nonzero elements is not continuous. Indeed, for a neighborhood of $1$ not containing $0$, e.g., $1 + 2\mathbb{Z}$, no neighborhood $1 + m\mathbb{Z}$ of $1$ will fit inside the set of reciprocals $\{\frac1{1 + 2n}: n \in \mathbb{Z}\}$. \end{remark} \begin{remark} \label{}\hypertarget{}{} If $K$ is a topological field, then either $K$ is a [[codiscrete space]] or is a [[Tychonoff space]]. The reason is that the closure of $\{0\}$ in a topological ring $K$ must be an [[ideal]] $I$, and since $K$ is a field, $I$ is either all of $K$ (whence $K$ is codiscrete), or $I = \{0\}$ in which case $K$ is a $T_1$-[[separation axiom|space]]. In the latter case, since a topological ring is a [[uniform space]], the $T_1$-condition implies $K$ is a Tychonoff space. \end{remark} \hypertarget{internalization}{}\subsection*{{Internalization}}\label{internalization} As discussed at [[field]], the notion of field is not algebraic in the sense of [[algebraic theory]], and there are various inequivalent ways of attempting to [[internal logic|internalize]] the notion inside structured categories. This issue is compounded in $Top$ by the fact that $Top$ has few of the exactness properties one needs to enact the more ``traditional'' fragments of first-order logic (such as being a [[pretopos]] or [[Heyting category]] or [[exact category]] or [[regular category]]). So it is a matter of interest to give a categorical definition of field that internalizes correctly in $Top$, as well as in other categories of interest. (Note that $Top$ does enjoy \emph{some} elementary exactness properties: it is a [[lextensive category]] with finite colimits. It also satisfies a strong non-elementary condition: it is $\infty$-extensive and the underlying-set functor $Top \to Set$ is a [[topological functor]]. Curiously, $Top^{op}$ is a [[regular category]].) \hypertarget{classical_internalization}{}\subsubsection*{{``Classical'' internalization}}\label{classical_internalization} One straightforward approach, at least if we are thinking along lines of [[excluded middle|classical logic]], is to define a field $K$ in terms of the following limit-colimit [[sketch]]: \begin{enumerate}% \item Introduce structure to make $K$ a commutative [[ring object]]: two binary operations $a: K \times K \to K$ (addition) and $m: K \times K \to K$ (multiplication), two constants $0: 1 \to K$ and $e: 1 \to K$ (additive and multiplicative identities), additive inversion $-: K \to K$, all subject to the usual equations for [[commutative rings]]; \item Letting $i: U \to K \times K$ denote the [[equalizer]] of $m: K \times K \to K$ and $e \circ !: K \times K \to 1 \to K$, add the axiom that $j = \pi_1 \circ i: U \to K \times K \to K$ (provably monic in finite limit logic) is a [[regular monomorphism]]: the [[equalizer]] of its [[cokernel pair]]; \item Add the axiom that $(0, j): 1 + U \to K$ (provably a disjoint embedding) is [[epimorphism|epic]]. \end{enumerate} Some commentary might be in order. Clearly $U$ plays the role of the [[group of units]] of $K$, realized as a [[subobject]] by $j: U \to K$. Axiom 3. says that $0$ and $U$ exhaust all of $K$, but without going so far to say that $(0, j): 1 + U \to K$ is an [[isomorphism]], an inappropriately strong condition in the case of $Top$ (as it would force the point $0: 1 \to K$ to be open, making $K$ a [[discrete space]]). Axiom 2. is more subtle: a mono $k: A \to B$ in $Top$ is regular iff $A$ has the subspace topology inherited from $B$ via $k$. So Axiom 2. interpreted in $Top$ says that the subspace topology on $U$ coming from its inclusion into $K$ coincides with the topology it has by definition, viz. the subspace topology coming from its embedding $i$ in $K \times K$. Notice that inversion on $U$ is continuous if we use the definitional topology, since inversion is effected by permuting the two factors of $K \times K$. Thus Axiom 2. is a sneaky way of forcing inversion on $U$ with the subspace topology from $K$ to be continuous (and in fact it is equivalent to continuity of inversion). \hypertarget{examples}{}\subsection*{{Examples}}\label{examples} \begin{itemize}% \item The [[real numbers]] with their [[metric topology]] as a [[Euclidean space]]; \item The [[complex numbers]], similarly, \end{itemize} etc. [[!redirects topological field]] [[!redirects topological fields]] \end{document}