Recall that a [[p-divisible group]] $G$ has the defining properties that $p \,id_G:G\to G$ is an epimorphism with finite kernel satisfying $G=\cup_j ker\, p^j \, id_G$. Now let $A$ be any commutative algebraic $k$-group such that $p\, id_A:A\to A$ is an epimorphism. Then $$A(p):=\cup_j ker \,p^j \,id_A$$ is a $p$-divisible group.