Professor Tom Lenagan has alerted me of a misstatement in Lemma 3.2 of the published version,
that is the Lemma 2 of math.QA/0604610 v2 version. The correction is as follows:
Let . Consider the subalgebra in generated by all where either or (possibly both) and its subalgebra generated by all where both and Let . Then for every , .
The proof is the same and rather easy; the occurence of in the second line of the proof is , in the rest stays.
All as in the published version, everywhere stays in the proof except that on should stay in the last paragraph that in fact belongs to the smaller subalgebra rather than , so it can serve as an input as in the Lemma 3.2.
Created on November 18, 2016 at 17:03:58. See the history of this page for a list of all contributions to it.