t = 0, A(2,1,3), B(5,2,2)
Isključimo varijablu t.
x = 2 + 3 t
3 t = x -2
t = x/3 -2/3
y = 1 + x/3 -2/3 = x/3 - 2/3
z = 3 - (x/3 - 2/3) = -x/3 + 7/3
R0(2,1,2)
R1(3,2,4)
R2(0,2,-1)
vector(R0,R1) = (1,1,2)
vector(R0,R2) = (-2,1,-3)
vector r(t) = (2,1,2)+u(1,1,2)+v(-2,1,-3)
r(t) = (2+u-2v, 1+u+v,2+2u-3v)
Last revised on November 16, 2020 at 18:35:37. See the history of this page for a list of all contributions to it.