# nLab small violations of choice

foundations

## Foundational axioms

foundational axiom

# Contents

## Statement

The axiom of small violations of choice, or SVC, introduced by Andreas Blass (1979), asserts that

• There exists a set $S$ such that every set is a subquotient of $A\times S$ for some choice set $A$.

Note that if $S=1$, then every set is a subquotient of a choice set; but choice sets are closed under subsets and quotients, so this means that every set is choice, i.e. that the axiom of choice holds. Thus, SVC is a weakened version of AC; intuitively, it says that “the failure of AC to hold is parametrized by a mere set” (rather than a proper class).

At least assuming classical logic, it is equivalent to say that every set is a quotient of $A\times S$, for we can extend any function defined on a subset of $A\times S$ to be constant on the complement of this subset.

## Implications

The following statements are all consequences of SVC (some requiring excluded middle).

## Models

SVC holds in all “ordinary” permutation and symmetric model?s of (material) set theory, as well as in hereditarily-ordinal-definable and relatively-constructible submodels. However, it can fail in permutation models over proper classes.

Mike Shulman: The above facts make it sound plausible that SVC might hold internally in all Grothendieck toposes constructed from a base topos satisfying AC, but Makkai claims that it does not (although its consequence, the (local) axiom of small cardinality selection, does).

## SVC and COSHEP

SVC can be regarded as a sort of “dual” or “complement” to COSHEP, since it deals with choice sets and COSHEP deals with projective sets. And while COSHEP implies the existence of projective resolutions, SVC implies the existence of (at least some) injective resolutions.

Moreover, at least assuming classical logic, SVC + COSHEP implies AC. First note that if SVC holds with $S$, then it also holds with $S'$ for any surjection $S'\to S$; thus under SVC + COSHEP we may assume that SVC holds with a projective set $S$. Let $Z$ be any set, and let $g\colon A\times S \twoheadrightarrow Z^S$ be a surjection, where $A$ is choice. For each $s\in S$, let $Z_s = \{g(a,s)(s) | a\in A\} \subseteq Z$. Then each $Z_s$ is a surjective image of $A$, and hence choice. If each $Z\setminus Z_s$ is nonempty, then (since $S$ is projective) we have a function $f\colon S\to Z$ such that $f(s)\notin Z_s$ for all $s$. But $g$ is surjective, so there exist $s_0\in S$ and $a_0\in A$ with $g(a_0,s_0) = f$, whence $g(a_0,s_0)(s_0) = f(s_0) \notin Z_{s_0}$, a contradiction. Thus some $Z_s$ is all of $Z$, and hence $Z$ is choice; so AC holds.

## References

SVC was introduced in the paper

• Andreas Blass, “Injectivity, projectivity, and the axiom of choice.” Trans. Amer. Math. Soc. 1979

where most of the above results were proven. Some others can be found in

• Michael Rathjen and Lubarsky, “Choice principles in constructive and classical set theories”.

Revised on July 21, 2015 10:12:13 by Urs Schreiber (82.113.99.224)