DStevenson Notes on classification of left fibrations

Given a left fibration X→SX\to S, we want to show that there is a map S→𝒮S\to \mathcal{S} such that X→SX\to S is induced from the universal left fibration 𝒮 1/→𝒮\mathcal{S}_{1/}\to \mathcal{S} in the sense that there is a homotopy pullback diagram (??in the Joyal model structure on S\mathbf{S}??)

X → 𝒮 1/ ↓ ↓ S → 𝒮 \array{ X & \rightarrow & \mathcal{S}_{1/} \\ \downarrow & & \downarrow \\ S & \rightarrow & \mathcal{S} }

Furthermore, we want to show that the classifying map S→𝒮S\to \mathcal{S} is unique up to equivalence.

Observe firstly that there are 1-1 correspondences between commutative diagrams

X → 𝒮 1/ ↓ ↓ S → 𝒮 \array{ X & \to & \mathcal{S}_{1/} \\ \downarrow & & \downarrow \\ S & \to & \mathcal{S} }

in S\mathbf{S}, maps

1⋆X∪ XS→𝒮 1\star X\cup_X S \to \mathcal{S}

in S\mathbf{S}, and finally simplicial functors

ℭ(1⋆X∪ XS)→Kan. \mathfrak{C}(1\star X\cup_X S)\to \mathbf{Kan}.

Let vv denote the cone point in 1⋆X1\star X and let ℳ\mathcal{M} denote a fibrant replacement of ℭ(1⋆X∪ XS)\mathfrak{C}(1\star X\cup_X S).

Then we obtain a simplicial functor

ℭ(1⋆X∪ XS)→Kan \mathfrak{C}(1\star X\cup_X S)\to \mathbf{Kan}

by the formula

Map ℳ(v,−):ℭ(1⋆X∪ XS)→Kan. \Map_{\mathcal{M}}(v,-)\colon \mathfrak{C}(1\star X\cup_X S)\to \mathbf{Kan}.
Revised on September 24, 2013 at 10:42:03 by Danny Stevenson