# Contents

## Idea

The Hochschild-Kostant-Rosenberg theorem identifies the Hochschild homology and -cohomology of certain algebras with Kähler differentials and derivations, respectively.

## Details

### For commutative $k$-algebras

First notice that we always have the following statement about the situation in degree 1.

###### Proposition

For a $k$-algebra $R$, its module of Kähler differentials coincides with its first Hochschild homology

$\Omega \left(R/k\right)\simeq {H}_{1}\left(R,R\right)\phantom{\rule{thinmathspace}{0ex}}.$\Omega(R/k) \simeq H_1(R,R) \,.

Write ${\Omega }^{0}\left(R/k\right):=R\simeq {\mathrm{HH}}_{0}\left(R,R\right)$.

The HKR-theorem generalizes this to higher degrees.

#### As an isomorphism of chain complexes

For $n\ge 2$ write ${\Omega }^{n}\left(R/k\right)={\wedge }_{R}^{n}\Omega \left(R/k\right)$ for the $n$-fold wedge product of $\Omega \left(R/k\right)$ with itself: the degree $n$-Kähler forms.

###### Theorem

The isomorphism ${\Omega }^{1}\left(R/k\right)\simeq {H}_{1}\left(R,R\right)$ extends to a graded ring morphism

$\psi :{\Omega }^{•}\left(R/k\right)\to {H}_{•}\left(R,R\right)\phantom{\rule{thinmathspace}{0ex}}.$\psi : \Omega^\bullet(R/k) \to H_\bullet(R,R) \,.

If the $k$-algebra $R$ is sufficiently well-behaved, then this morphism is an isomorphism that identifies the Hochschild homology of $R$ in degree $n$ with ${\Omega }^{n}\left(R/k\right)$ for all $n$:

###### Theorem

(Hochschild-Kostant-Rosenberg theorem)

If $k$ is a field and $A$ a commutative $k$-algebra which is

• essentially of finite type (finitely presented)

• smooth over $k$, meaning:

• the $A$-module of Kähler differentials ${\Omega }_{k}^{1}\left(A\right)$ is a projective object in $A\mathrm{Mod}$k.

then there is an isomorphism of graded $k$-algebras

$\psi :{\Omega }^{•}\left(A/k\right)\stackrel{\simeq }{\to }{H}_{•}\left(A,A\right)\phantom{\rule{thinmathspace}{0ex}}.$\psi : \Omega^\bullet(A/k) \stackrel{\simeq}{\to} H_\bullet(A,A) \,.

Moreover, dually, there is an isomorphism of Hochschild cohomology with wedge products of derivations:

${\wedge }_{A}^{•}{\mathrm{Der}}_{k}\left(A,A\right)\simeq {\mathrm{HH}}^{•}\left(A,A\right)\phantom{\rule{thinmathspace}{0ex}}.$\wedge^\bullet_A Der_k(A,A) \simeq HH^\bullet(A,A) \,.
###### Proof

This is reviewed for instance as theorem 9.4.7 of

or as theorem 9.1.3 in Ginzburg.

#### As an isomorphism of $\infty$-algebras

Actually, the HKR theorem holds on the level of chains: there is a quasi-isomorphism of chain complexes from polyvector fields (with zero differential) to the Hochschild cochain complex (with Hochschild differential).

The HKR map is a map of dg vector spaces, but not a map of dg-algebras nor a map of dg-Lie algebras. However, the formality theorem of Maxim Kontsevich states that nevertheless the HKR map can be extended to an ${L}_{\infty }$ quasi-isomorphism. See this MO post for details.

The HKR map is only an isomorphism of vector spaces, not an isomorphism of algebras. In order to make it an isomorphism of algebras, one must add a “correction” by the square root of the $\stackrel{^}{A}$ class. This is analogous to the Duflo isomorphism. See Kontsevich and Caldararu.

### For non-commutative algebras

There is also a noncommutative analogue due to Alain Connes.

(…)

## References

The original source is

Standard textbook references include

A new approach to the generalized HKR isomorphism is proposed in

• Dima Arinkin, Andrei Caldararu, When is the self-intersection of a subvariety a fibration?, arxiv/1007.1671

Revised on September 4, 2013 19:36:46 by Anonymous Coward (130.209.66.110)