nLab scaling degree of a distribution

Contents

Contents

Idea

The scaling degree or degree of divergence (Steinmann 71) or more generally the degree (Weinstein 78) of a distribution on Cartesian space ℝ n\mathbb{R}^n is a measure for how it behaves at the origin 0∈ℝ n0 \in \mathbb{R}^n under rescaling x↦λxx \mapsto \lambda x of the canonical coordinates.

The concept controls the problem of extension of distributions from the complement ℝ n∖{0}\mathbb{R}^n \setminus \{0\} of the origin to all of ℝ n\mathbb{R}^n. Such extensions are important notably in the construction of perturbative quantum field theories via causal perturbation theory, where the freedom in the choice of such extensions models the ("re"-)normalization freedom (“counter-terms”) in the construction.

Definition

Definition

(rescaled distribution)

Let n∈ℕn \in \mathbb{N}. For λ∈(0,∞)⊂ℝ\lambda \in (0,\infty) \subset \mathbb{R} a positive real number write

ℝ n ⟶s λ ℝ n x ↦ λx \array{ \mathbb{R}^n &\overset{s_\lambda}{\longrightarrow}& \mathbb{R}^n \\ x &\mapsto& \lambda x }

for the diffeomorphism given by multiplication with λ\lambda, using the canonical real vector space-structure of ℝ n\mathbb{R}^n.

Then for u∈𝒟′(ℝ n)u \in \mathcal{D}'(\mathbb{R}^n) a distribution on the Cartesian space ℝ n\mathbb{R}^n the rescaled distribution is the pullback of uu along m λm_\lambda

u λ≔s λ *u∈𝒟′(ℝ n). u_\lambda \coloneqq s_\lambda^\ast u \;\in\; \mathcal{D}'(\mathbb{R}^n) \,.

Explicitly, this is given by

𝒟(ℝ n) ⟶⟨u λ,−⟩ ℝ b ↦ λ −n⟨u,b(λ −1⋅(−))⟩. \array{ \mathcal{D}(\mathbb{R}^n) &\overset{ \langle u_\lambda, - \rangle}{\longrightarrow}& \mathbb{R} \\ b &\mapsto& \lambda^{-n} \langle u , b(\lambda^{-1}\cdot (-))\rangle } \,.

Similarly for X⊂ℝ nX \subset \mathbb{R}^n an open subset which is invariant under s λs_\lambda, the rescaling of a distribution u∈𝒟′(X)u \in \mathcal{D}'(X) is is u λ≔s λ *uu_\lambda \coloneqq s_\lambda^\ast u.

Definition

(scaling degree of a distribution)

Let n∈ℕn \in \mathbb{N} and let X⊂ℝ nX \subset \mathbb{R}^n be an open subset of Cartesian space which is invariant under rescaling s λs_\lambda (def. ) for all λ∈(0,∞)\lambda \in (0,\infty), and let u∈𝒟′(X)u \in \mathcal{D}'(X) be a distribution on this subset. Then

  1. The scaling degree of uu is the infimum

    sd(u)≔inf{ω∈ℝ|limλ→0λ ωu λ=0} sd(u) \;\coloneqq\; inf \left\{ \omega \in \mathbb{R} \;\vert\; \underset{\lambda \to 0}{\lim} \lambda^\omega u_\lambda = 0 \right\}

    of the set of real numbers ω\omega such that the limit of the rescaled distribution λ ωu λ\lambda^\omega u_\lambda (def. ) vanishes. If there is no such ω\omega one sets sd(u)≔∞sd(u) \coloneqq \infty.

  2. The degree of divergence of uu is the difference of the scaling degree by the dimension of the underlying space:

deg(u)≔sd(u)−n. deg(u) \coloneqq sd(u) - n \,.

Examples

Example

(scaling degree of non-singular distributions)

If u=u fu = u_f is a non-singular distribution given by bump function f∈C ∞(X)⊂𝒟′(X)f \in C^\infty(X) \subset \mathcal{D}'(X), then its scaling degree (def. ) is non-positive

sd(u f)≤0. sd(u_f) \leq 0 \,.

Specifically if the first non-vanishing partial derivative ∂ αf(0)\partial_\alpha f(0) of ff at 0 occurs at order |α|∈ℕ{\vert \alpha\vert} \in \mathbb{N}, then the scaling degree of u fu_f is −|α|-{\vert \alpha\vert}.

Proof

By definition we have for b∈C cp ∞(ℝ n)b \in C^\infty_{cp}(\mathbb{R}^n) any bump function that

⟨λ ω(u f) λ,n⟩ =λ ω−n∫ℝ nf(x)g(λ −1x)d nx =λ ω∫ℝ nf(λx)g(x)d nx, \begin{aligned} \left\langle \lambda^{\omega} (u_f)_\lambda, n \right\rangle & = \lambda^{\omega-n} \underset{\mathbb{R}^n}{\int} f(x) g(\lambda^{-1} x) d^n x \\ & = \lambda^{\omega} \underset{\mathbb{R}^n}{\int} f(\lambda x) g(x) d^n x \end{aligned} \,,

where in last line we applied change of integration variables.

The limit of this expression is clearly zero for all ω>0\omega \gt 0, which shows the first claim.

If moreover the first non-vanishing partial derivative of ff occurs at order |α|=k{\vert \alpha \vert} = k, then Hadamard's lemma says that ff is of the form

f(x)=(∏iα i!) −1(∂ αf(0))∏i(x i) α i+∑β∈ℕ n|β|=|α|+1∏i(x i) β ih β(x) f(x) \;=\; \left( \underset{i}{\prod} \alpha_i ! \right)^{-1} (\partial_\alpha f(0)) \underset{i}{\prod} (x^i)^{\alpha_i} + \underset{ {\beta \in \mathbb{N}^n} \atop { {\vert \beta\vert} = {\vert \alpha \vert} + 1 } }{\sum} \underset{i}{\prod} (x^i)^{\beta_i} h_{\beta}(x)

where the h βh_{\beta} are smooth functions. Hence in this case

⟨λ ω(u f) λ,n⟩ =λ ω+|α|∫ℝ n(∏iα i!) −1(∂ αf(0))∏i(x i) α ib(x)d nx =+λ ω+|α|+1∫ℝ n∏i(x i) β ih β(x)b(x)d nx. \begin{aligned} \left\langle \lambda^{\omega} (u_f)_\lambda, n \right\rangle & = \lambda^{\omega + {\vert \alpha\vert }} \underset{\mathbb{R}^n}{\int} \left( \underset{i}{\prod} \alpha_i ! \right)^{-1} (\partial_\alpha f(0)) \underset{i}{\prod} (x^i)^{\alpha_i} b(x) d^n x \\ & \phantom{=} + \lambda^{\omega + {\vert \alpha\vert} + 1} \underset{\mathbb{R}^n}{\int} \underset{i}{\prod} (x^i)^{\beta_i} h_{\beta}(x) b(x) d^n x \end{aligned} \,.

This makes manifest that the expression goes to zero with λ→0\lambda \to 0 precisely for ω>−|α|\omega \gt - {\vert \alpha \vert}, which means that

sd(u f)=−|α| sd(u_f) = -{\vert \alpha \vert}

in this case.

Example

(scaling degree of derivatives of delta-distributions)

Let α∈ℕ n\alpha \in \mathbb{N}^n be a multi-index and ∂ αδ∈𝒟′(X)\partial_\alpha \delta \in \mathcal{D}'(X) the corresponding partial derivatives of the delta distribution δ 0∈𝒟′(ℝ n)\delta_0 \in \mathcal{D}'(\mathbb{R}^n) supported at 00. Then the degree of divergence (def. ) of ∂ αδ 0\partial_\alpha \delta_0 is the total order the derivatives

deg(∂ αδ 0)=|α| deg\left( {\, \atop \,} \partial_\alpha\delta_0{\, \atop \,} \right) \;=\; {\vert \alpha \vert}

where |α|≔∑iα i{\vert \alpha\vert} \coloneqq \underset{i}{\sum} \alpha_i.

Proof

By definition we have for b∈C cp ∞(ℝ n)b \in C^\infty_{cp}(\mathbb{R}^n) any bump function that

⟨λ ω(∂ αδ 0) λ,b⟩ =(−1) |α|λ ω−n(∂ |α|∂ α 1x 1⋯∂ α nx nb(λ −1x)) |x=0 =(−1) |α|λ ω−n−|α|∂ |α|∂ α 1x 1⋯∂ α nx nb(0), \begin{aligned} \left\langle \lambda^\omega (\partial_\alpha \delta_0)_\lambda, b \right\rangle & = (-1)^{{\vert \alpha \vert}} \lambda^{\omega-n} \left( \frac{ \partial^{{\vert \alpha \vert}} }{ \partial^{\alpha_1} x^1 \cdots \partial^{\alpha_n}x^n } b(\lambda^{-1}x) \right)_{\vert x = 0} \\ & = (-1)^{{\vert \alpha \vert}} \lambda^{\omega - n - {\vert \alpha\vert}} \frac{ \partial^{{\vert \alpha \vert}} }{ \partial^{\alpha_1} x^1 \cdots \partial^{\alpha_n}x^n } b(0) \end{aligned} \,,

where in the last step we used the chain rule of differentiation. It is clear that this goes to zero with λ\lambda as long as ω>n+|α|\omega \gt n + {\vert \alpha\vert}. Hence sd(∂ αδ 0)=n+|α|sd(\partial_{\alpha} \delta_0) = n + {\vert \alpha \vert}.

Example

(scaling degree of Feynman propagator on Minkowski spacetime)

Let

Δ F(x)=limϵ∈(0,∞)ϵ→0+i(2π) p+1∫∫ −∞ ∞e ik μx μ−k μk μ−(mcℏ) 2+iϵdk 0d pk→ \Delta_F(x) \;=\; \underset{ {\epsilon \in (0,\infty)} \atop {\epsilon \to 0} }{\lim} \frac{+i}{(2\pi)^{p+1}} \int \int_{-\infty}^\infty \frac{ e^{i k_\mu x^\mu} }{ - k_\mu k^\mu - \left( \tfrac{m c}{\hbar} \right)^2 + i \epsilon } \, d k_0 \, d^p \vec k

be the Feynman propagator for the massive free real scalar field on n=p+1n = p+1-dimensional Minkowski spacetime (this prop.). Its scaling degree is

sd(Δ F) =n−2 =p−1. \begin{aligned} sd(\Delta_{F}) & = n - 2 \\ & = p -1 \end{aligned} \,.

(Brunetti-Fredenhagen 00, example 3 on p. 22)

Proof

Regarding Δ F\Delta_F as a generalized function via the given Fourier-transform expression, we find by change of integration variables in the Fourier integral that in the scaling limit the Feynman propagator becomes that for vannishing mass, which scales homogeneously:

limλ→0(λ ωΔ F(λx)) =limλ→0(λ ωlimϵ∈(0,∞)ϵ→0+i(2π) p+1∫∫ −∞ ∞e ik μλx μ−k μk μ−(mcℏ) 2+iϵdk 0d pk→) =limλ→0(λ ω−nlimϵ∈(0,∞)ϵ→0+i(2π) p+1∫∫ −∞ ∞e ik μλx μ−(λ −2)k μk μ−(mcℏ) 2+iϵdk 0d pk→) =limλ→0(λ ω−n+2limϵ∈(0,∞)ϵ→0+i(2π) p+1∫∫ −∞ ∞e ik μλx μ−k μk μ+iϵdk 0d pk→). \begin{aligned} \underset{\lambda \to 0}{\lim} \left( \lambda^\omega \; \Delta_F(\lambda x) \right) & = \underset{\lambda \to 0}{\lim} \left( \lambda^{\omega} \underset{ {\epsilon \in (0,\infty)} \atop {\epsilon \to 0} }{\lim} \frac{+i}{(2\pi)^{p+1}} \int \int_{-\infty}^\infty \frac{ e^{i k_\mu \lambda x^\mu} }{ - k_\mu k^\mu - \left( \tfrac{m c}{\hbar} \right)^2 + i \epsilon } \, d k_0 \, d^p \vec k \right) \\ & = \underset{\lambda \to 0}{\lim} \left( \lambda^{\omega-n} \; \underset{ {\epsilon \in (0,\infty)} \atop {\epsilon \to 0} }{\lim} \frac{+i}{(2\pi)^{p+1}} \int \int_{-\infty}^\infty \frac{ e^{i k_\mu \lambda x^\mu} }{ - (\lambda^{-2}) k_\mu k^\mu - \left( \tfrac{m c}{\hbar} \right)^2 + i \epsilon } \, d k_0 \, d^p \vec k \right) \\ & = \underset{\lambda \to 0}{\lim} \left( \lambda^{\omega-n + 2 } \; \underset{ {\epsilon \in (0,\infty)} \atop {\epsilon \to 0} }{\lim} \frac{+i}{(2\pi)^{p+1}} \int \int_{-\infty}^\infty \frac{ e^{i k_\mu \lambda x^\mu} }{ - k_\mu k^\mu + i \epsilon } \, d k_0 \, d^p \vec k \right) \,. \end{aligned}

Properties

Proposition

(basic properties of scaling degree of distributions)

Let X⊂ℝ nX \subset \mathbb{R}^n and u∈𝒟′(X)u \in \mathcal{D}'(X) be a distribution as in def. , such that its scaling degree is finite: sd(u)<∞sd(u) \lt \infty (def. ). Then

  1. For α∈ℕ n\alpha \in \mathbb{N}^n, the partial derivative of distributions ∂ α\partial_\alpha increases scaling degree at most by |α|{\vert \alpha\vert }:

    deg(∂ αu)≤deg(u)+|α| deg(\partial_\alpha u) \;\leq\; deg(u) + {\vert \alpha\vert}
  2. For α∈ℕ n\alpha \in \mathbb{N}^n, the product of distributions with the smooth coordinate functions x αx^\alpha decreases scaling degree at least by |α|{\vert \alpha\vert }:

    deg(x αu)≤deg(u)−|α| deg(x^\alpha u) \;\leq\; deg(u) - {\vert \alpha\vert}
  3. Under tensor product of distributions their scaling degrees add:

    sd(u⊗v)≤sd(u)+sd(v) sd(u \otimes v) \leq sd(u) + sd(v)

    for v∈𝒟′(Y)v \in \mathcal{D}'(Y) another distribution on Y⊂ℝ n′Y \subset \mathbb{R}^{n'};

  4. deg(fu)≤deg(u)−kdeg(f u) \leq deg(u) - k for f∈C ∞(X)f \in C^\infty(X) and f (α)(0)=0f^{(\alpha)}(0) = 0 for |α|≤k−1{\vert \alpha\vert} \leq k-1;

(Brunetti-Fredenhagen 00, lemma 5.1, Dütsch 18, exercise 3.34)

Proof

The first three statements follow with manipulations as in example and example .

For the fourth…

Proposition

(scaling degree of product distribution)

Let u,v∈𝒟′(ℝ n)u,v \in \mathcal{D}'(\mathbb{R}^n) be two distributions such that

  1. both have finite degree of divergence (def. )

    deg(u),deg(v)<∞ deg(u), deg(v) \lt \infty
  2. their product of distributions is well-defined

    uv∈𝒟′(ℝ n) u v \in \mathcal{D}'(\mathbb{R}^n)

    (in that their wave front sets satisfy Hörmander's criterion)

then the product distribution has degree of divergence bounded by the sum of the separate degrees:

deg(uv)≤deg(u)+deg(v). deg(u v) \;\leq\; deg(u) + deg(v) \,.

(Brunetti-Fredenhagen 00, special case of lemma 6.6)

References

The concept of scaling degree is due to

  • O. Steinmann, Perturbation Expansions in Axiomatic Field Theory, volume 11 of Lecture Notes in Physics, Springer, Berlin Springer Verlag, 1971.

and the more general concept of degree due to

  • Alan Weinstein, The order and symbol of a distribution, Trans. Amer. Math. Soc. 241, 1–54 (1978).

Review and further developments in the context of ("re"-)normalization in causal perturbation theory/pAQFT is in

Last revised on March 28, 2018 at 15:20:37. See the history of this page for a list of all contributions to it.