Let $E$ be the class of final functors and $M$ be the class of discrete fibrations. Then $(E,M)$ is an orthogonal factorization system of Cat, called the comprehensive factorization system.
Let $F:C\to D$ be a functor. Define $K:D\to Set$ as the left Kan extension of the constant presheaf $C\to Set$ at the singleton along $F$. Explicitly, $K(d)$ is the set of connected components of $F/d$. Let $E=\int K$, so an object of $E$ is an ordered pair $(d, [\alpha:Fc\to d])$ where $[\alpha]$ denotes the connected component of $(c,\alpha)$. Then it is not hard to verify that $e:C\to E$ mapping $c\mapsto (Fc,[id_{fc}])$ is final, the canonical $m:E\to D$ is a discrete fibration, and $F=me$.
Now we show that $E$ and $M$ are replete subcategories of $Cat$. Clearly they include all isomorphisms.
If functors $F:C\to D$ and $G: D\to E$ are final, then we show that $G\circ F$ is final. For $e\in E$, there is a element $(d,\alpha:e\to Gd)$ of $e/G$, and thence an element $(c,\beta:d\to Fc)$ of $d/F$, so we obtain an element $(c, e \stackrel{\alpha}{\to} Gd \stackrel{G\beta}{\to} GFc)$ of $e/GF$. Now we must show that any two elements $(c,\gamma:e\to GFc),(c',\gamma':e\to GFc')$ are connected. Since $G$ is final, elements $(Fc,\gamma)$ and $(Fc',\gamma')$ of $e/G$ are connected. It suffices to consider the case of a zig-zag of length one: a morphism $f:Fc\to Fc'$ such that
By finality of $F$, the elements $(c,id:Fc\to Fc)$ and $(c', f:Fc\to Fc')$ of $Fc/F$ are connected. A zig-zag path between them, by precomposition with $\gamma$, becomes a zig-zag path between $(c,\gamma)$ and $(c',\gamma')$. So $G\circ F$ is final.
The proof that discrete fibrations form a subcategory is omitted.
Now we must show that the lifting problem
has a unique solution $h$ when $e\in E$ and $m\in M$.
We prove uniqueness first. For $b\in B$, let $(a,\alpha:b\to e(a))\in b/e$. Then $h(\alpha)$ must be the unique lifting of $g(\alpha)$, and $h(b)$ the domain of this lifting, proving uniqueness of $h$ on objects. For $\beta:b\to b'$ in $B$, $h(\beta)$ must be the unique lifting of $g(\beta)$, so $h$ is unique (if it exists).
Now we must show that this $h$ is well-defined, functorial, and a solution to the lifting problem. If $(a',\alpha':b\to e(a'))$ is another element of $b/e$, then WLOG let $u:a\to a'$ such that
Lifting this diagram, we see that $g(\alpha)$ and $g(\alpha')$ must lift to morphisms with identical domain, so $h$ is well-defined on objects.
For $\beta:b\to b'$ in $B$, let $\alpha:b'\in e(a)$, and by the diagram
we see that $g(\beta)$ and $g(\alpha\circ\beta)$ must lift to morphisms with identical domains, so $h(\beta)$ has domain $h(b)$.
Functoriality now follows easily from uniqueness of lifting for a discrete fibration, and it is not hard to show that $h$ is a solution to the lifting problem.
Note there is a mistake in the proof of the main theorem of the paper above, as noted on page 74 of:
Max Kelly, Basic concepts of enriched category theory, London Math. Soc. Lec. Note Series 64, Cambridge Univ. Press (1982), Reprints in Theory and Applications of Categories 10 (2005) 1-136 [ISBN:9780521287029, tac:tr10, pdf]
Fosco Loregian, Emily Riehl, Categorical Notions of Fibration, Expositiones Mathematicae 38, 2020. (arXiv:1806.06129, doi:10.1016/j.exmath.2019.02.004)
Clemens Berger, Ralph M. Kaufmann, Comprehensive Factorization Systems, Tbilisi Math. J. 10 (2017), 255-277 (doi:10.1515/tmj-2017-0112)
Paolo Perrone, Walter Tholen, Kan extensions are partial colimits, Kan Extensions are Partial Colimits. Applied Categorical Structures 30, 685–753 (2022). (arXiv:2101.04531. doi:10.1007/s10485-021-09671-9)
Internal comprehensive factorisations (and torsors) are considered in:
Last revised on October 27, 2023 at 19:19:12. See the history of this page for a list of all contributions to it.