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orthogonal factorization system

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Definition

Orthogonal factorization systems

Definition

Let C be a category and let (E,M) be two classes of morphisms in C. We say that (E,M) is an orthogonal factorization system if (E,M) is a weak factorization system in which solutions to lifting problems are unique.

We spell out several equivalent explicit formulation of what this means.

Definition

(E,M) is an orthogonal factorization system if every morphism f in C factors f=r as a morphism E followed by a morphism rM; and the following equivalent conditions hold

  1. We have:

    1. E is precisely the class of morphisms that are left orthogonal to every morphism in M;

    2. M is precisely the class of morphisms that are right orthogonal to every morphism in E.

  2. We have:

    1. The factorization is unique up to unique isomorphism.

    2. E and M both contain all isomorphisms and are closed under composition.

  3. We have:

    1. E and M are replete subcategories of the arrow category C I.

    2. Every morphism in E is left orthogonal to every morphism in M.

OFS’s are traditionally called just factorization systems. See the Catlab for more of the theory.

An orthogonal factorization system is called proper if every morphism in E is an epimorphism and every morphism in M is a monomorphism.

Prefactorization systems

For any class E of morphisms in C, we write E for the class of all morphisms that are right orthogonal to every morphism in E. Dually, given M we write M for the class of all morphisms that are left orthogonal to every morphism in M. The second condition in the definition of an OFS then says that E= M and M=E .

In general, () and () form a Galois connection on the poset of classes of morphisms in C. A pair (E,M) such that E= M and M=E is sometimes called a prefactorization system. Note that by generalities about Galois connections, for any class A of maps we have prefactorization systems ( (A ),A ) and ( A,( A) ). We call these generated and cogenerated by A, respectively.

Properties

General

Proposition

The different characterization in def. 2 are indeed all equivalent.

Proof

(…)

For the moment see (Joyal).

(…)

Proposition

A weak factorization system (L,R) is an orthogonal factorization system precisely if LR.

Proof

(…)

For the moment see (Joyal).

(…)

Proposition

For (L,R) an orthogonal factorization system in a category C, the intersection LR is precisely the class of isomorphisms in C.

Proof

If is clear that every isomorphism is in LR. Conversely, let f:AB be a morphism in LR. This implies that the two trivial factorizations

f=Aid AAfBf = A \stackrel{id_A}{\to} A \stackrel{f}{\to} B

and

f=AfBid BBf = A \stackrel{f}{\to} B \stackrel{id_B}{\to} B

are both (L,R)-factorization. Therefore there is a unique morphism f˜ in the commuting diagram

A id A A f f¯ f B id B B.\array{ A &\stackrel{id_A}{\to}& A \\ \downarrow^{\mathrlap{f}} &\nearrow_{\bar f}& \downarrow^{\mathrlap{f}} \\ B &\stackrel{id_B}{\to}& B } \,.

This says precisely that f¯ is a left and right inverse of f.

Closure properties

A prefactorization system (E,M) (and hence, also, a factorization system) satisfies the following closure properties. We state them for M, but E of course satisfies the dual property.

  • M contains the isomorphisms and is closed under composition and pullback (insofar as pullbacks exist in C).
  • If a composite fg is in M, and f is either in M or a monomorphism, then g is in M.
  • M is closed under all limits in the arrow category Arr(C).

If C is a locally presentable category, then for any small set of maps A, the prefactorization system ( (A ),A ) is actually a factorization system. The argument is by a transfinite construction similar to the small object argument.

On the other hand, if (E,M) is any prefactorization system for which M consists of monomorphisms and C is complete and well-powered, then (E,M) is actually a factorization system. (Of course, there is a dual statement as well.) In fact something slightly more general is true; see M-complete category for this and other related ways to construct factorization systems.

Cancellation properties

Proposition

For (L,R) an orthogonal factorization system. Let

Y f g X gf Z\array{ && Y \\ & {}^{\mathllap{f}}\nearrow && \searrow^{\mathrlap{g}} \\ X && \stackrel{g \circ f}{\to} && Z }

be two composable morphisms. Then

  • If f and gf are in L, then so is g.

  • If g and gf are in R, then so is f.

Proof

Consider the first case. The second is directly analogous.

Choose an (L,R)-factorization of g

g:YIrZ.g : Y \stackrel{\ell}{\to} I \stackrel{r}{\to} Z \,.

With this we have lifting diagrams of the form

X gf Z f id Z Y r id Z I r ZX f Y I gf r 1 r Z id Z id Z Z\array{ X &\stackrel{g \circ f}{\to}& Z \\ \downarrow^{\mathrlap{f}} && \downarrow^{id_Z} \\ Y & \nearrow_r& \\ \downarrow^{\mathrlap{\ell}} && \downarrow^{id_Z} \\ I &\stackrel{r}{\to}& Z } \;\;\;\;\;\;\; \;\;\;\;\;\;\; \array{ X &\stackrel{f}{\to}& Y &\stackrel{\ell}{\to}& I \\ {}^{\mathllap{g \circ f}}\downarrow & & \nearrow_{r^{-1}}& & \downarrow^{\mathrlap{r}} \\ Z &\underset{id_Z}{\to}& &\underset{id_Z}{\to}& Z }

exhibiting an inverse of r. Therefore r is an isomorphism, hence is in L, by prop. 3, hence so is the composite f=r.

Examples

Several classical examples of OFS (E,M):

References

Revised on November 28, 2012 15:17:04 by Urs Schreiber (82.169.65.155)