nLab
regular and exact completions

Idea

The forgetful 2-functors

• from regular categories to lex categories,
• from exact categories to lex categories, and
• from exact categories to regular categories

have left adjoints, and in fact are (2-)monadic. Their left adjoints are called (free) regular or exact completions.

In the third case the 2-monad is idempotent, so the left adjoint can properly be called a completion, while in the first two cases, the 2-monad is only lax-idempotent?, so the left adjoint should technically be called a free completion. However, the phrases regular completion and exact completion are also commonly used for the first two cases. To disambiguate the second and third cases the phrases ex/lex completion and ex/reg completion are also used, and so by analogy the first case is called reg/lex completion.

In fact, the reg/lex and ex/lex completion can be applied to a category that merely has weak finite limits, although in this case the sense in which the construction is “free” is more complicated.

Todd Trimble: Hi Mike. Thanks very much for writing this article. Could you clarify for me your use of parentheticals below in the case of reg/lex completion? I am guessing that all parentheticals like “(weak)” can be safely ignored in the case where $C$ is actually finitely complete (as opposed to weakly finitely complete), so that, for example, the objects of $C_{\mathrm{reg}/\mathrm{lex}}$ can in that case be taken to be pairs $(c,e)$ where $e$ is a kernel pair of a morphism $f:c\to d$, and morphisms $(c,e)\to (c\prime ,e\prime )$ are morphisms $c\to c\prime$ which respect the equivalence relations.

If my guess is correct, I think I might have found it easier to read if the finitely complete case were run through first, followed by discussion of what modifications are to be made in the case of weak finite completeness, rather than discussing the two cases simultaneously using parentheticals.

Also, I wasn’t able to find under Properties something about the reg/lex completion I was expecting or hoping to find. (My immediate interest in this is the example of equilogical spaces as regular completion of $\mathrm{Top}$.) Is there supposed to be a property along the lines that the regular completion is cartesian closed if $C$ has weak exponentials, and locally cartesian closed if $C$ has weak dependent products? (I don’t have ready access to the literature, so these should be treated as guesses.)

Mike Shulman: You’re exactly right about the meaning of the parentheticals. Sorry for writing that in kind of a confusing way. Your guess is exactly right, and your suggestion is a good one; see if you think it’s clearer now.

I’m surprised to realize that I omitted the conditions for (local) cartesian closure of the reg/lex completion, since one needs them to conclude that it preserves lextensive quasitoposes. The only conditions I can find in the literature require somewhat more than mere weak (local) cartesian closure of $C$. The point being that the set of function from a quotient of $X$ to a quotient of $Y$ may, in general, be only a quotient of the set of functions from $X$ to $Y$, so we need some way to ensure that that quotient exists in $C_{\mathrm{reg}/\mathrm{lex}}$ since it doesn’t have all quotients. But $\mathrm{Top}$ does satisfy those conditions, so equilogical spaces are locally cartesian closed.

Todd: Thanks again; I think the section on regular completion does read more clearly now, and the material you added to Properties is very helpful. I think what you wrote on equilogical spaces might fit well in Examples, as would realizability toposes as examples of exact completions. If I have time soon I might write down something stubby here.

Constructions

The ex/lex completion

There are several constructions of the ex/lex completion. Perhaps the quickest one to state (Hu-Tholen 1996) is that if $C$ is small, then $C_{\mathrm{ex}/\mathrm{lex}}$ is the full subcategory of its presheaf category ${\mathrm{Set}}^{C^{\mathrm{op}}}$ spanned by those presheaves $F$ such that

• $F$ admits a regular epimorphism $y(X)\twoheadrightarrow F$ from a representable presheaf,
• with the additional property that if $K\rightrightarrows y(X)$ is the kernel pair of $y(X)\twoheadrightarrow F$, then $K$ also admits a regular epi $y(Z)\to K$ from a representable presheaf.

A more explicit construction is as follows. Let us think, informally, of the objects of $C$ as presets and the morphisms of $C$ as “proofs”. An object of $C_{\mathrm{ex}}=C_{\mathrm{ex}/\mathrm{lex}}$ will then be a “set” or setoid constructed from $C$. Precisely, we take the objects of $C_{\mathrm{ex}}$ to be the pseudo-equivalence relations in $C$: a pseudo-equivalence relation consists of:

• an object $X\in C$ and
• a parallel pair $s,t:R\rightrightarrows X$, such that
• there exists an arrow $i:X\to R$ with $si=ti=1_X$,
• there exists an arrow $v:R\to R$ with $sv=t$ and $tv=s$, and
• there exists an arrow $c:R{\times }_{X}R\to R$ with $sc=s{\pi }_1$ and $tc=t{\pi }_2$. (If $C$ has merely weak finite limits, we assert this for some, and hence every, weak pullback $R{\times }_X^{w}R$.)

If $(s,t):R\to X\times X$ is a monomorphism, then these conditions make it precisely a congruence or internal equivalence relation in $C$. In general, we can think of the fiber of $R$ over $(x_1,x_2)$ as giving a collection of “reasons” or “proofs” that $x_{1}R{x}_2$. Then $i$ supplies a uniform proof that $xRx$ for every $x$, while $v$ supplies a uniform proof that $xRy$ implies $yRx$, and $c$ supplies a uniform proof thath $xRy$ and $yRz$ imply $xRz$.

If $R\rightrightarrows X$ and $S\rightrightarrows Y$ are two pseudo-equivalence relations, a morphism between them in $C_{\mathrm{ex}}$ is defined to be a morphism $f:X\to Y$ in $C$, such that there exists a morphism $f_1:R\to S$ with $s{f}_1=fs$ and $t{f}_1=ft$. That is, $f_1$ supplies a uniform proof that if $xRy$ then $f(x)Sf(y)$. Moreover, we declare two such morphisms $f,g:X\to Y$ to be equal if there exists a morphism $h:X\to S$ such that $sh=f$ and $th=g$ (that is, a uniform proof that $f(x)Sg(x)$). Because $S\rightrightarrows Y$ is a pseudo-equivalence relation, this defines an actual equivalence relation on the morphisms $f:X\to Y$, which is compatible with composition; thus we have a well-defined category $C_{\mathrm{ex}}$.

We have a full and faithful functor $C\to C_{\mathrm{ex}}$ sending an object $X$ to the pseudo-equivalence relation $X\rightrightarrows X$. One can then verify directly that $C_{\mathrm{ex}}$ is exact, that this embedding preserves finite limits, and that it is universal with respect to lex functors from $C$ into exact categories.

There are also other constructions. Of course, the ex/lex completion can also be obtained by composing (any construction of) the reg/lex completion with (any construction of) the ex/reg completion.

The reg/lex completion

The reg/lex completion $C_{\mathrm{reg}}=C_{\mathrm{reg}/\mathrm{lex}}$ of a lex category $C$ is perhaps most succinctly described as the subcategory of $C_{\mathrm{ex}}$ consisting of those objects which admit monomorphisms into objects of $C$. That is, instead of adding all quotients of pseudo-equivalence relations in $C$, we only add those quotients which are necessary in order to be able to construct images of morphisms in $C$. For many construction of $C_{\mathrm{ex}}$, this idea can then be made more explicit and sometimes simplified.

For instance, if we regard $C_{\mathrm{ex}}$ as a full subcategory of ${\mathrm{Set}}^{C^{\mathrm{op}}}$ as above, then we can likewise regard $C_{\mathrm{reg}}$ as the full subcategory of ${\mathrm{Set}}^{C^{\mathrm{op}}}$ determined by those presheaves $F$ such that

• $F$ admits a regular epimorphism $y(X)\twoheadrightarrow F$ from a representable presheaf, and
• $F$ admits a monomorphism $F\rightarrowtail y(Z)$ into a representable presheaf.

If we construct $C_{\mathrm{ex}}$ using pseudo-equivalence relations, as above, then we can characterize the pseudo-equivalence relations which we need to form $C_{\mathrm{reg}}$ as precisely the kernel pairs of morphisms of $C$ (or finite families of such). Therefore, we obtain an equivalent definition of $C_{\mathrm{reg}}$ as follows. Its objects are morphisms of $C$ (regarded as stand-ins for their formally added images). A morphism from $p:X\to Y$ to $q:Z\to W$ should be a morphism $f:X\to Z$ for which there exists an $f_1$ relating the kernel of $p$ to the kernel of $q$, modulo an equivalence relation generated by maps from $X$ to the kernel of $q$. But by definition of kernel pairs, two morphisms will be identified under this latter equivalence relation if and only if they have the same composite with $q$, so it makes sense to define the morphisms of $C_{\mathrm{reg}}$ from $p:X\to Y$ to $q:Z\to W$ to be certain morphisms $\overline{f}:X\to W$ which factor through $q$ (non-uniquely). We still have to impose the condition that $f$ should preserve the kernel pairs, but in terms of $\overline{f}$ this is simply the statement that $\overline{f}r=\overline{f}s$, where $(r,s)$ is the kernel pair of $p$. This is the definition of $C_{\mathrm{reg}}$ given in the Elephant.

We can then verify that $C_{\mathrm{reg}}$ is regular, that we have a full and faithful functor $C\to C_{\mathrm{reg}}$, which preserves finite limits, and is universal among lex functors from $C$ to regular categories. Again, there are also other constructions.

Also, just as for the free exact completion, the construction works essentially the same if $C$ has only weak finite limits. In this case, instead of the objects of $C_{\mathrm{ex}}$ admitting a monomorphism to a single object of $C$, we have to consider those admitting a jointly-monic finite family of morphisms into objects of $C$, with similar modifications for the other descriptions.

The ex/reg completion

If $C$ is regular, a quick definition of $C_{\mathrm{ex}/\mathrm{reg}}$ is as the full subcategory of the category $\mathrm{Sh}(C)$ of sheaves for the regular coverage on $C$ spanned by those sheaves which are quotients of congruences in $C$. (Lack 1999)

A more explicit description can be obtained by first passing from $C$ to its allegory of internal relations, then splitting the idempotents which are equivalence relations in $C$, and finally reconstructing a regular category from the resulting allegory. Yet more explicitly, this means that the objects of $C$ are congruences in $C$, and the morphisms are relations which are entire and functional relative to the given congruences.

The higher categorical approach

A somewhat more unified approach to all these completions can be obtained as follows. Observe that in the classical situation (that is, in the presence of choice), sets can be identified with all of the following:

• 0-trivial groupoids, i.e. groupoids in which any two parallel morphisms are equal, i.e. equivalence relations.
• 0-trivial 2-groupoids, i.e. 2-groupoids in which any two parallel 2-morphisms are equal and any two parallel 1-morphisms are isomorphic.
• and so on…
• 0-trivial n-groupoids for any $0\le n\le \mathrm{\infty }$.

In the absence of choice, this is still true as long as the morphisms between 0-trivial n-groupoids are $n$-anafunctors. If instead we consider only actual functors, however, in the absence of choice what we obtain are various completions of $\mathrm{Set}$. Specifically:

• ${\mathrm{Set}}_{\mathrm{reg}/\mathrm{lex}}$ can be identified with the category whose objects are 0-trivial groupoids, and whose morphisms are natural isomorphism classes of functors.
• ${\mathrm{Set}}_{\mathrm{ex}/\mathrm{lex}}$ can be identified with the category whose objects are 0-trivial 2-groupoids, and whose morphisms are pseudonatural equivalence classes of 2-functors. In the notion of 2-groupoid here we also demand that each 1-cell be equipped with a specified inverse equivalence.

This idea can be generalized to provide alternate constructions of the completions for an arbitrary $C$ with finite limits. The notions of internal $n$-category and internal $n$-functor in such a $C$ make perfect sense for any $n$. The same is true of the notion of $n$-groupoid, as long as we interpret this to mean the structure of “inverse-assigning” morphisms in $C$. The statement “any two parallel $n$-cells are equal” also makes sense in any lex category, since it demands that a certain specified morphism is monic. Finally, we can also interpret “any two parallel $k$-cells are equivalent” algebraically by specifying a particular equivalence between any such pair. (Note that for $k=(n-1)$, since parallel $n$-cells are equal there is a unique way to do this.) We thereby obtain a notion of internal 0-trivial $n$-groupoid in any lex category, and we write $0\mathrm{triv}n\mathrm{Gpd}(C)$ for the category of such things and internal $n$-natural equivalence classes of functors. We then have:

• It is fairly clear from the above explicit description that $C_{\mathrm{reg}/\mathrm{lex}}$ is the full subcategory of $0\mathrm{triv}1\mathrm{Gpd}(C)$ determined by the kernel pairs (which are congruences, i.e. internal 0-trivial 1-groupoids). If, like $\mathrm{Set}$, $C$ is already exact, so that every congruence is a kernel pair, then $C_{\mathrm{reg}/\mathrm{lex}}\simeq 0\mathrm{triv}1\mathrm{Gpd}(C)$.

• $C_{\mathrm{ex}/\mathrm{lex}}$ is always equivalent to $0\mathrm{triv}2\mathrm{Gpd}(C)$. To see this, note that a pseudo-equivalence relation (together with chosen maps $i$, $c$, and $v$) can be regarded as the 1-skeleton of an internal bicategory in $C$ with specified inverse equivalences for every 1-cell. There is then a unique way to add 2-cells to make it a 0-trivial bigroupoid.

It is not clear how 0-trivial $n$-groupoids fit into this picture for $n>2$, although it seems likely that the objects of iterated reg/lex and ex/lex completions can be identified with some type of internal n-fold category.

Now if $C$ is already regular, then we can define a notion of internal anafunctor between internal $n$-categories. It is then easily seen that

• $C_{\mathrm{ex}/\mathrm{reg}}$ is equivalent to the category of 0-trivial 1-groupoids, and natural isomorphism classes of internal anafunctors between them.

Again, it is not entirely clear how the 0-trivial $n$-groupoids and anafunctors behave for $n>1$, although it seems fairly likely (to me) that in this case the process will stabilize at $n=1$, i.e. 0-trivial $n$-groupoids with equivalence classes of ana-$n$-functors will give $C_{\mathrm{ex}/\mathrm{reg}}$ for all $n\ge 1$.

Properties of regular and exact completions

Many categorical properties of interest are preserved by one or more of the regular and exact completions. That is, if $C$ has these properties, then so does the completion, and the inclusion functor preserves them. Note that frequently, for a completion to have some structure, it suffices for $C$ to have a “weak” version of that structure.

• Of course, finite limits are preserved by all three completions. In fact, as we have remarked, for the ex/lex and reg/lex completions, $C$ need only have weak finite limits.

• $C$ is lextensive if and only if $C_{\mathrm{ex}/\mathrm{lex}}$ is, and if and only if $C_{\mathrm{reg}/\mathrm{lex}}$ is, and in this case the embeddings preserve coproducts (Menni 2000). It follows that if $C$ is a pretopos, then so is $C_{\mathrm{ex}/\mathrm{lex}}$, although the inclusion $C\to C_{\mathrm{ex}/\mathrm{lex}}$ is not a “pretopos functor” as it does not preserve regular epis.

• If $C$ is lextensive and has coequalizers (and hence has finite colimits), then so do $C_{\mathrm{ex}/\mathrm{lex}}$ and $C_{\mathrm{reg}/\mathrm{lex}}$ (Menni 2000). However, the inclusion functors do not preserve coequalizers. In fact, it suffices for $C$ to be lextensive with quasi-coequalizers, meaning that for every $f,g:Y\rightrightarrows X$ there exists $q:X\to Q$ with $qf=qg$, such that for any $h:X\to Z$ with $hf=hg$, $h$ coequalizes the kernel pair of $q$.

• The categories $C_{\mathrm{reg}/\mathrm{lex}}$ and $C_{\mathrm{ex}/\mathrm{lex}}$ always have enough (regular) projectives. In fact, the objects of $C$ are precisely the projective objects of these categories. Moreover, an exact category $D$ is of the form $C_{\mathrm{ex}/\mathrm{lex}}$ for some $C$ (with weak finite limits) if and only if it has enough projectives, in which case of course $C$ can be taken to be the subcategory of projectives (Carboni–Vitale 1998). Note that if $D$ has enough projectives, then its subcategory of projectives always has weak finite limits. Similarly, a regular category $D$ is of the form $C_{\mathrm{reg}/\mathrm{lex}}$ for some $C$ (with weak finite limits) if and only if it has enough projectives and every object can be embedded in a projective one.

• If $C$ is a regular category satisfying the “regular” axiom of choice (i.e. every regular epi splits), then it is equivalent to $C_{\mathrm{reg}/\mathrm{lex}}$, and hence the latter also satisfies the axiom of choice. Similarly, if $C$ is exact and satisfies choice, then it is equivalent to $C_{\mathrm{ex}/\mathrm{lex}}$. Conversely, if the inclusion $C\to C_{\mathrm{reg}/\mathrm{lex}}$ or $C\to C_{\mathrm{ex}/\mathrm{lex}}$ is an equivalence, then since the objects of $C$ are projective in these completions, $C$ must satisfy the axiom of choice.

  In fact, if we assume merely that $C_{\mathrm{ex}/\mathrm{lex}}\to (C_{\mathrm{ex}/\mathrm{lex}}{)}_{\mathrm{ex}/\mathrm{lex}}$ is a equivalence, then since the objects of $C_{\mathrm{ex}/\mathrm{lex}}$ are projective in $(C_{\mathrm{ex}/\mathrm{lex}}{)}_{\mathrm{ex}/\mathrm{lex}}$, they must also all be projective in $C_{\mathrm{ex}/\mathrm{lex}}$, and therefore $C\to C_{\mathrm{ex}/\mathrm{lex}}$ is also an equivalence. It follows by induction that if the sequence of iterations of $(-{)}_{\mathrm{ex}/\mathrm{lex}}$ stabilizes at any finite stage, it must in fact stabilize at the very beginning and $C$ must satisfy the axiom of choice. A similar argument applies to the reg/lex completion. (The ex/reg completion, of course, always stabilizes after one application.)

• Cartesian closure is preserved by the ex/lex completion (Carboni–Rosolini 2000). In fact, $C_{\mathrm{ex}/\mathrm{lex}}$ is cartesian closed if and only if $C$ has weak simple products, meaning weak dependent product?s along product projections.

• Local cartesian closure is also preserved by the ex/lex completion (Carboni–Rosolini 2000). In fact, $C_{\mathrm{ex}/\mathrm{lex}}$ is locally cartesian closed if and only if $C$ is weakly locally cartesian closed, meaning that each slice category has weak dependent products. It follows in particular that if $C$ is a Π-pretopos, then so is $C_{\mathrm{ex}/\mathrm{lex}}$. For each $\Pi$-pretopos $C$ we thus obtain a sequence $C$, $C_{\mathrm{ex}}$, $(C_{\mathrm{ex}}{)}_{\mathrm{ex}}$, … of $\Pi$-pretopoi, which in general does not stabilize.

• (Local) cartesian closure is seemingly not always preserved by the reg/lex completion, but it is under certain hypotheses. Recalling that $C_{\mathrm{reg}/\mathrm{lex}}$ is the full subcategory of $C_{\mathrm{ex}/\mathrm{lex}}$ consisting of the kernel pairs, suppose that $C$ has pullback-stable (epi,regular mono) factorizations and that every regular congruence is a kernel pair. Then $C_{\mathrm{reg}/\mathrm{lex}}$ is reflective in $C_{\mathrm{ex}/\mathrm{lex}}$ (BCRS 1998, Menni 2000): the reflection of a pseudo-equivalence relation $R\rightrightarrows X$ is its (epi,regular mono) factorization. Moreover, the reflection preserves products, and also pullbacks along maps in $C_{\mathrm{reg}/\mathrm{lex}}$, from which it follows that if $C_{\mathrm{ex}/\mathrm{lex}}$ is cartesian closed or locally cartesian closed, so is $C_{\mathrm{reg}/\mathrm{lex}}$.

  Thus, if $C$ is weakly cartesian closed (resp. weakly locally cartesian closed), has pullback-stable (epi,regular mono) factorizations, and every regular congruence is a kernel pair, then $C_{\mathrm{reg}/\mathrm{lex}}$ is cartesian closed (resp. locally cartesian closed). In particular, the local versions of these hypotheses apply in particular to Top and to any quasitopos. Note that ${\mathrm{Top}}_{\mathrm{reg}/\mathrm{lex}}$ is called the category of equilogical spaces.

• If $C$ is lextensive with coequalizers (or “quasi-coequalizers”) and a strong-subobject classifier, then so is $C_{\mathrm{reg}/\mathrm{lex}}$ (Menni 2000). It follows that if $C$ is a lextensive quasitopos, then so is $C_{\mathrm{reg}/\mathrm{lex}}$. For each lextensive quasitopos $C$ we thus obtain a sequence $C$, $C_{\mathrm{reg}}$, $(C_{\mathrm{reg}}{)}_{\mathrm{reg}}$, … of lextensive quasitopoi, which in general does not stabilize.

• If $C$ has a natural numbers object, then so do $C_{\mathrm{reg}/\mathrm{lex}}$ and $C_{\mathrm{ex}/\mathrm{lex}}$. (Does $C_{\mathrm{ex}/\mathrm{reg}}$? What about more general W-types?)

• $C_{\mathrm{ex}/\mathrm{lex}}$ is an elementary topos iff $C$ has weak dependent products and a generic proof (Menni 2000). Note that if $C$ is a topos satisfying the axiom of choice, then its subobject classifier is a generic proof. It follows that in this case $C_{\mathrm{ex}/\mathrm{lex}}$ is a topos—but we already knew that, because $C_{\mathrm{ex}/\mathrm{lex}}$ is equivalent to $C$ for such a $C$.

• If $C$ is regular, locally cartesian closed, and has a generic mono, i.e. a monomorphism $\tau :\Upsilon \to \Lambda$ such that every monomorphism is a pullback of $\tau$ (not necessarily uniquely), then $C_{\mathrm{ex}/\mathrm{reg}}$ is a topos (Menni 2000).

On the other hand, some properties are not preserved by the completions.

• Of course, all the completions are regular categories, but the inclusions are not regular functor?s, since they do not preserve regular epis.

• We have seen that the existence of a subobject classifier or power objects is not, in general, preserved by the completions (although if $C$ is a topos, then of course so is $C_{\mathrm{ex}/\mathrm{reg}}$, since it is equivalent to $C$).

• Similarly, if $C$ is well-powered, it does not follow that $C_{\mathrm{reg}/\mathrm{lex}}$ or $C_{\mathrm{ex}/\mathrm{lex}}$ are. In particular, for $X\in C$, the subobject preorders ${\mathrm{Sub}}_{C_{\mathrm{reg}/\mathrm{lex}}}(X)$ and ${\mathrm{Sub}}_{C_{\mathrm{ex}/\mathrm{lex}}}(X)$ are equivalent to the preorder reflection of the slice category $C/X$, and it is easy to construct examples in which this is not small.

• If $C$ is a coherent category, it does not follow that $C_{\mathrm{ex}/\mathrm{lex}}$ or $C_{\mathrm{reg}/\mathrm{lex}}$ is. However, if $C$ is additionally lextensive, we have seen above that so are these completions, and hence in particular also coherent (any extensive regular category is coherent). One can also write down the “free coherent completion” and the “free pretopos completion” of a lex category, and the “pretopos completion” of a coherent category; see familial regularity and exactness for some clues on how to proceed.

• If $C$ is a Heyting category, it does not follow that $C_{\mathrm{ex}/\mathrm{lex}}$ or $C_{\mathrm{reg}/\mathrm{lex}}$ is. However, if $C$ is additionally lextensive and locally cartesian closed, we have seen above that so are these completions, and hence Heyting (any lextensive locally cartesian closed regular category is Heyting).

• Unsurprisingly, if $C$ is a Boolean category, it does not follow that $C_{\mathrm{ex}/\mathrm{lex}}$ or $C_{\mathrm{reg}/\mathrm{lex}}$ is, even if $C$ is lextensive and LCC so that its completions are Heyting.

  In fact, a stronger statement is true: if $C$ is lextensive and regular, then $C_{\mathrm{reg}/\mathrm{lex}}$ and $C_{\mathrm{ex}/\mathrm{lex}}$ are Boolean if and only if $C$ satisfies the axiom of choice (in which case they are of course equivalent to $C$). More precisely, if $X\in C$ is such that every subobject of $X$ in $C_{\mathrm{reg}/\mathrm{lex}}$ is complemented, then $X$ is projective in $C$. (The same argument applies to $C_{\mathrm{ex}/\mathrm{lex}}$.) For suppose that $p:Y\to X$ is a regular epi in $C$. Recall that ${\mathrm{Sub}}_{C_{\mathrm{reg}/\mathrm{lex}}}(X)$ is the preorder reflection of $C/X$. Thus $p$, considered as an object of $C/X$, defines a monomorphism in $C_{\mathrm{reg}/\mathrm{lex}}$. By assumption, this monic is complemented; let its complement be represented by $q:Z\to X$. Since complements are disjoint, and meets in ${\mathrm{Sub}}_{C_{\mathrm{reg}/\mathrm{lex}}}(X)$ are given by pullbacks in $C/X$, the pullback of $p$ and $q$ admits a morphism to the initial object $0$, and hence is itself initial since $C$ is extensive. Now $p$ is regular epi, hence so is its pullback $0\to Z$. But in a lextensive regular category, disjointness of the coproduct $1+1$ implies that $0\to 1$ is the equalizer of of the coprojections $1\rightrightarrows 1+1$, and therefore any epimorphism with domain $0$ is an isomorphism; thus $Z$ is also initial. Now since joins in ${\mathrm{Sub}}_{C_{\mathrm{reg}/\mathrm{lex}}}(X)$ are given by coproducts in $C/X$, the induced map $Y+Z\to X$ must become an isomorphism in ${\mathrm{Sub}}_{C_{\mathrm{reg}/\mathrm{lex}}}(X)$, which means that it must admit a section; but since $Z$ is initial this means that $p$ itself has a section.

• If $C$ is well-pointed, it does not follow that $C_{\mathrm{ex}/\mathrm{lex}}$ or $C_{\mathrm{reg}/\mathrm{lex}}$ are (in the stronger sense appropriate for non-toposes). It is of course always true that $1$ is projective in the completions, and if it is a generator in $C$ then it will also be so in the completions. And if $C$ is lextensive, so that its completions are coherent, then $1$ is indecomposable in them as soon as it is so in $C$. However, it does not follow that $1$ is a strong generator in the completions even if it is so in $C$, since the completions have (in general) many more monomorphisms than $C$ does.

  Of course, if $C$ is a well-pointed topos such that $C_{\mathrm{ex}/\mathrm{lex}}$ is also a topos, then the latter is also well-pointed, since any generator in a topos is a strong generator.

Examples

(to be written…)

• The category $\mathrm{TF}$ of torsion-free abelian groups is regular, but not exact. For instance, the congruence $\{(a,b)\mid a\equiv bmod2\}\subseteq \mathbb{Z}\times \mathbb{Z}$ is not a kernel in $\mathrm{TF}$. Unsurprisingly, the ex/reg completion of $\mathrm{TF}$ is equivalent to the category $\mathrm{Ab}$ of all abelian groups.

  Note that although $\mathrm{TF}$ is not exact, its inclusion into $\mathrm{Ab}$ does have a left adjoint (quotient by torsion), and thus $\mathrm{TF}$ is cocomplete. Herein lies a subtle trap for the unwary: since the ex/reg completion monad is idempotent, it is in particular lax-idempotent, which means that any left adjoint to the unit $C\hookrightarrow C_{\mathrm{ex}/\mathrm{reg}}$ is in fact a (pseudo) algebra structure; but since the monad is actually idempotent, any algebra structure is an equivalence. Of course, the reflection $\mathrm{Ab}\to \mathrm{TF}$ is not an equivalence, which doesn’t contract the general facts because this left adjoint is not a regular functor, and hence not an adjunction in the 2-category on which the monad $(-{)}_{\mathrm{ex}/\mathrm{reg}}$ lives. In fact, it is not hard to check that $C\hookrightarrow C_{\mathrm{ex}/\mathrm{reg}}$ has a left adjoint in $\mathrm{Cat}$ if and only if $C$ has coequalizers of congruences (while if it has a left adjoint in $\mathrm{Reg}$ then it must be an equivalence).

References

• Carboni and Celia Magno, “The free exact category on a left exact one”, J. Austral. Math. Soc. (Ser. A), 1982.

• Hu and Tholen, “A note on free regular and exact completions and their infinitary generalizations”, TAC 1996.

• Carboni and Vitale, “Regular and exact completions”, JPAA 1998.

• Birkedal and Carboni and Rosolini and Scott, “Type Theory via Exact Categories,” 1998

• Stephen Lack, “A note on the exact completion of a regular category, and its infinitary generalizations” TAC 1999.

• The Elephant, Sections A1.3 and A3.

• Carboni and Rosolini, “Locally cartesian closed exact completions”, JPAA 2000

• Matías Menni, “Exact completions and toposes,” Ph.D. Thesis, University of Edinburgh, 2000.