nLab dual net of von Neumann algebras

Redirected from "Haag dual".
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Context

AQFT

algebraic quantum field theory (perturbative, on curved spacetimes, homotopical)

Introduction

Concepts

field theory:

Lagrangian field theory

quantization

quantum mechanical system, quantum probability

free field quantization

gauge theories

interacting field quantization

renormalization

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States and observables

Operator algebra

Local QFT

Perturbative QFT

Contents

Idea

Duality for nets of von Neumann algebras is a concept that was introduced for local nets in the Haag-Kastler approach to quantum field theory. Many results of this approach need some sort of duality in the sense described here or close to it as a precondition.

Definition

Let (M k)(M_k) be a net of von Neumann algebras with a causal index set II that is a causal net of algebras. Let RR be the global algebra of the net, that is

R=( kM k) R = (\bigcup_k M_k){''}

An index iIi \in I satisfies duality if

M i=( jiM j)R=( jiM j )R= jiM j c M_i = (\bigcup_{j \perp i} M_j)' \bigcap R = (\bigcap_{j \perp i} M_j^') \bigcap R = \bigcap_{j \perp i} M^c_j

Here M j cM^c_j is the relative commutant of M jM_j with respect to RR.

The net is called dual if every index is dual i.e. satisfies duality.

A weaker concept is that of essentially dual:

Define an extension (M^ k)(\hat M_k) of the net (M k)(M_k) via

M^ i=( jiM j) \hat M_i = (\bigcup_{j \perp i} M_j)'

This extension is not necessarily a causal net anymore. If it is, then it is dual by definition. The net (M k)(M_k) is essentially dual, if the extended net (M^ k)(\hat M_k) is dual, which is true iff (M^ k)(\hat M_k) is causal.

The net (M k)(M_k) is called maximal if there is no proper extension which satisfies the causality condition?.

Examples

A Haag-Kastler vacuum representation satisfies Haag duality if every double cone aka diamond is a dual index. The reason for this relaxation is that full duality of every index is often too restrictive, so that the less restrictive Haag duality plays an important role in the theory.

Let J 0J_0 be the index set of diamonds, a Haag-Kastler vacuum representation is essentially Haag dual if the net M(J 0)M(J_0) (that is the original net restricted to diamonds as indices) is essentially dual.

Last revised on July 9, 2011 at 13:42:19. See the history of this page for a list of all contributions to it.