basic constructions:
strong axioms
further
A large cardinal stronger than Reinhardt cardinals that is inconsistent with ZF with countable choice. In order to remove the inconsistency, one has to remove the axiom of countable choice to get bare ZF + a club Berkeley cardinal.
In ZF, a cardinal is a club Berkeley cardinal if it is regular and, for every club set (closed and unbounded set) and every transitive set containing , there exists a non-trivial elementary embedding such that its critical point lands exactly inside that club: .
Last revised on September 22, 2026 at 04:53:48. See the history of this page for a list of all contributions to it.