nLab Tor

Idea

In the context of homological algebra, the $Tor$-functor is the derived tensor product: the left derived functor of the tensor product of $R$-modules, for $R$ a commutative ring.

Together with the Ext-functor it constitutes one of the central operations of interest in homological algebra.

Definition

Given a ring $R$ the bifunctor $\otimes_R : Mod_{R} \times {}_{R}Mod\to Ab$ from two copies of $R$-Mod to Ab is a right exact functor. Its left derived functors are the Tor-functors

$$Tor(-,B) : Mod_R \to Ab$$

and

$$Tor(A,-) : {}_{R}Mod \to Ab$$

with respect to one argument with fixed another, if they exist, are parts of a bifunctor

$$Tor : Mod_{R}\times {}_{R}Mod\to Ab \,.$$

Properties

Existence and balancing

Given a right $R$-module

$$A \in Mod_R$$

and a left $R$-module

$$B \in {}_R Mod$$

there are in principle three different ways to compute their derived tensor product $Tor_\bullet(A,B)$:

1. keeping $B$ fixed and deriving the functor

   $$(-) \otimes_R B : Mod_R \to Ab$$

2. keeping $A$ fixed and deriving the functor

   $$A \otimes_R (-) : {}_R Mod \to Ab$$

3. deriving the functor

   $$(-) \otimes_R (-) : Mod_R \times {}_R Mod \to Ab$$

   in both arguments

Theorem

If both $Mod_{R}$ and $_{R}Mod$ have enough projectives, then all these three derived functors exist and all give the same result.

Proof

Existence is clear from the very definition of derived functor in homological algebra. So we show that deriving in the left argument gives the same result as deriving in the right argument.

Let $Q^A_\bullet \stackrel{\simeq_{qi}}{\to} A$ and $Q^B_\bullet \stackrel{\simeq_{qi}}{\to} B$ be projective resolutions of $A$ and $B$, respectively. The corresponding tensor product of chain complexes $Tot (Q^A_\bullet\otimes Q^B_\bullet)$, hence the total complex of the degreewise tensor product of modules double complex carries the filtration by horizontal degree as well as that by vertical degree.

Accordingly there are the corresponding two spectral sequences of a double complex, to be denoted here $\{{}^{A}E^r_{p,q}\}_{r,p,q}$ (for the filtering by $A$-degree) and $\{{}^{B}E^r_{p,q}\}_{r,p,q}$ (for the filtering by $B$-degree). By the discussion there, both converge to the chain homology of the total complex.

We find the value of both spectral sequences on low degree pages according to the general discussion at spectral sequence of a double complex - low degree pages.

The 0th page for both is

$${}^A E^0_{p,q} = {}^B E^0_{p,q} \coloneqq Q^A_p \otimes_R Q^B_q \,.$$

For the first page we have

$$\begin{aligned} {}^A E^1_{p,q} & \simeq H_q(C_{p,\bullet}) \\ & \simeq H_q( Q^A_p \otimes Q^B_\bullet ) \end{aligned}$$

and

$$\begin{aligned} {}^B E^1_{p,q} & \simeq H_q(C_{\bullet,p}) \\ & \simeq H_q( Q^A_\bullet \otimes Q^B_p ) \end{aligned} \,.$$

Now using the universal coefficient theorem in homology and the fact that $Q^A_\bullet$ and $Q^B_\bullet$ is a resolution by projective objects, by construction, hence of tensor acyclic objects for which all Tor-modules vanish, this simplifies to

$$\begin{aligned} {}^A E^1_{p,q} & \simeq Q^A_p \otimes H_q(Q^B_\bullet) \\ & \simeq \left\{ \array{ Q^A_p \otimes_R B & if\; q = 0 \\ 0 & otherwise } \right. \end{aligned}$$

and similarly

$$\begin{aligned} {}^B E^1_{p,q} & \simeq H_q(Q^A_\bullet) \otimes_R Q^B_p \\ & \simeq \left\{ \array{ A \otimes_R Q^B_p & if\; q = 0 \\ 0 & otherwise } \right. \end{aligned} \,.$$

It follows for the second pages that

$$\begin{aligned} {}^A E^2_{p,q} & \simeq H_p(H^{vert}_q(Q^A_\bullet \otimes Q^B_\bullet)) \\ & \simeq \left\{ \array{ (L_p( (-)\otimes_R B ))(A) & if \; q = 0 \\ 0 & otherwise } \right. \end{aligned}$$

and

$$\begin{aligned} {}^B E^2_{p,q} & \simeq H_p(H^{hor}_q(Q^A_\bullet \otimes Q^B_\bullet)) \\ & \simeq \left\{ \array{ (L_p ( A \otimes_R (-) ))(B) & if \; q = 0 \\ 0 \; otherwise } \right. \end{aligned} \,.$$

Now both of these second pages are concentrated in a single row and hence have converged on that page already. Therefore, since they both converge to the same value:

$$L_p((-)\otimes_R B)(A) \simeq {}^A E^2_{p,0} \simeq {}^A E^\infty_{p,0} \simeq {}^B E^2_{p,0} \simeq L_p(A \otimes_R (-))(B) \,.$$

Respect for direct sums and filtered colimits

Proposition

Each $Tor_n^R(-,N)$ respects direct sums.

Proof

Let $S \in$ Set and let $\{N_s\}_{s \in S}$ be an $S$-family of $R$-modules. Observe that

1. if $\{(F_s)_\bullet\}_{s \in S}$ is an family of projective resolutions, then their degreewise direct sum $(\oplus_{s \in S} F)_\bullet$ is a projective resolution of $\oplus_{s \in S} N_s$.

2. the tensor product functor distributes over direct sums (this is discussed at tensor product of modules – monoidal category structure)

3. the chain homology functor preserves direct sums (this is discussed at chain homology - respect for direct sums).

Using this we have

$$\begin{aligned} Tor_n^R(\oplus_{s \in S} N_s, N) & \simeq H_n\left( \left(\oplus_{s \in S} F\right) \otimes N \right) \\ & \simeq H_n\left( \oplus_{s \in S} \left(F_s \otimes N \right) \right) \\ & \simeq \oplus_{s \in S} H_n( F_s \otimes N ) \\ & \simeq \oplus_{s \in S} Tor_n(N_s, N) \end{aligned} \,.$$

Proposition

Each $Tor_n^R(-,N)$ respects filtered colimits.

Proof

Let hence $A \colon I \to R Mod$ be a filtered diagram of modules. For each $A_i$, $i \in I$ we may find a projective resolution and in fact a free resolution $(Y_i)_\bullet \stackrel{\simeq_{qi}}{\to} A$. Since chain homology commutes with filtered colimits (this is discussed at chain homology - respect for filtered colimits), this means that

$$(\underset{\to_i}{\lim} Y_i)_\bullet \to A$$

is still a quasi-isomorphism. Moreover, by Lazard's criterion the degreewise filtered colimits of free modules $\underset{\to_i}{\lim} (Y_i)_n$ for each $n \in \mathbb{N}$ are flat modules. This means that $\underset{\to_i}{\lim} (Y_i)_\bullet \to A$ is flat resolution of $A$. By the very definition or else by the basic properties of flat modules, this means that it is a $(-)\otimes N$-acyclic resolution. By the discussion there it follows that

$$Tor_n^\mathbb{Z}(A,N) \simeq H_n( (\underset{\to_i}{\lim} Y_i) \otimes N ) \,.$$

Now the tensor product of modules is a left adjoint functor (the right adjoint being the internal hom of modules) and so it commutes over the filtered colimit to yield, using again that chain homology commutes with filtered colimits,

$$\begin{aligned} \cdots & \simeq H_n( \underset{\to_i}{\lim} (Y_i \otimes N) ) \\ & \simeq \underset{\to_i}{\lim} H_n( Y_i \otimes N ) \\ & \simeq \underset{\to_i}{\lim} Tor_n( A_i, N) \end{aligned} \,.$$

Relation to torsion groups

An abelian group is called torsion if its elements are “nilpotent”, hence if all its elements have finite order.

Definition

For $A \in$ Ab and $p \in \mathbb{N}$, write

$${}_p A \coloneqq \{ a \in A | p \cdot a = 0 \}$$

for the $p$-torsion subgroup consisting of all those elements whose $p$-fold sum with themselves gives 0.

For $n \in \mathbb{N}$ with $n \geq 1$, write $\mathbb{Z}_n = \mathbb{Z}/n\mathbb{Z}$ for the cyclic group of order $n$, as usual.

Proposition

For $p \in \mathbb{N}$, $p \geq 1$, and $A \in$ Ab $\simeq \mathbb{Z}$Mod any abelian group, we have an isomorphism

$$Tor_1^\mathbb{Z}(\mathbb{Z}_p, A) \simeq {}_p A$$

of the $Tor_1$-group with the $p$-torsion subgroup of $A$.

For $p = 0$ we have

$$Tor_1^{\mathbb{Z}}(\mathbb{Z}, A) \simeq 0 \,.$$

Proof

For the first statement, the short exact sequence

$$0 \to \mathbb{Z} \stackrel{\cdot p}{\to} \mathbb{Z} \stackrel{mod\, p}{\to} \mathbb{Z}_p \to 0$$

constitutes a projective resolution (even a free resolution) of $\mathbb{Z}_p$. Accordingly we have

$$\begin{aligned} Tor_1^\mathbb{Z}(\mathbb{Z}_p, A) &\simeq H_1( [\cdots\to 0 \to \mathbb{Z}\otimes A \stackrel{(\cdot p) \otimes A}{\to} \mathbb{Z} \otimes A ) \\ & \simeq ker( (\cdot p) \otimes A ) \\ & \simeq \{ a\in A | p\cdot a = 0 \} \end{aligned} \,.$$

Here in the last step we use that $(\cdot p)\otimes A$ acts as

$$\begin{aligned} (1, a) &\mapsto (p,a) \\ & = p \cdot (1,a) \\ & = (1, p \cdot a) \end{aligned} \,.$$

For the second statement, $\mathbb{Z}$ is already free hence $[\cdots \to 0 \to 0 \to \mathbb{Z}]$ is already a projective resolution and hence $Tor_1(\mathbb{Z}, A) \simeq H_1(0) \simeq 0$.

Proposition

Let $A$ be a finite abelian group and $B$ any abelian group. Then $Tor_1(A,B)$ is a torsion group. Specifically, $Tor_1(A,B)$ is a direct sum of torsion subgroups of $A$.

Proof

By a fundamental fact about finite abelian groups (see this theorem), $A$ is a direct sum of cyclic group $A \simeq \oplus_k \mathbb{Z}_{p_k}$. By prop. $Tor_1$ respects this direct sum, so that

$$Tor_1(A,B) \simeq \oplus_k Tor_1(\mathbb{Z}_{p_k}, B) \,.$$

By prop. every direct summand on the right is a torsion group and hence so is the whole direct sum.

More generally we have:

Proposition

Let $A$ and $B$ be abelian groups. Write $Tor^\mathbb{Z}$ for the left derived functor of tensoring over $R = \mathbb{Z}$. Then

1. $Tor^\mathbb{Z}_1(A,B)$ is a torsion group. Specifically it is a filtered colimit of torsion subgroups of $B$.

2. $Tor^{\mathbb{Z}}_1(\mathbb{Q}/\mathbb{Z}, A)$ is the torsion subgroup of $A$.

3. $A$ is a torsion-free group precisely if $Tor^\mathbb{Z}_1(A,-) = 0$, equivalently if $Tor^\mathbb{Z}_1(-,A) = 0$.

For instance (Weibel, prop. 3.1.2, prop. 3.1.3, cor. 3.1.5).

Proof

The group $A$ may be expressed as a filtered colimit

$$A \simeq \underset{\to_i}{\lim} A_i$$

of finitely generated subgroups (this is discussed at Mod - Limits and colimits). Each of these is a direct sum of cyclic groups.

By prop. $Tor_1^\mathbb{Z}(-,B)$ preserves these colimits. By prop. every cyclic group is sent to a torsion group (of either $A$ or $B). Therefore by prop.$Tor_1(A,B)$ is a filtered colimit of direct sums of torsion groups. This is itself a torsion group.

Remark

Analogous results fail, in general, for $\mathbb{Z}$ replaced by another ring $R$.

Corollary

An [[abelian group]] is [[torsion subgroup|torsion free]] precisely if regarded as a $\mathbb{Z}$-[[module]] it is a [[flat module]].

See at flat module - Examples for more.

Symmetry in the two arguments

Proposition

For $N_1, N_2 \in R Mod$ and $n \in \mathbb{N}$ there is a [[natural isomorphism]]

$$Tor_n(A,B) \simeq Tor_n(B,A) \,.$$

We first give a proof for $R$ a [[principal ideal domain]] such as $\mathbb{Z}$.

Proof

Let $R$ be a [[principal ideal domain]] such as $\mathbb{Z}$ (in the latter case $R$[[Mod]]$\simeq$ [[Ab]]). Then by the discussion at projective resolution – length-1 resolutions there is always a [[short exact sequence]]

$$0 \to F_1 \to F_0 \to N \to 0$$

exhibiting a [[projective resolution]] of any module $N$. It follows that $Tor_{n \geq 2}(-,-) = 0$.

Let then $0 \to F_1 \to F_2 \to N_2 \to 0$ be such a short resolution for $N_2$. Then by the long exact sequence of a derived functor this induces an [[exact sequence]] of the form

$$0 \to Tor_1(N_1, F_1) \to Tor_1(N_1, F_0) \to Tor_1(N_1, N_2) \to N_1 \otimes F_1 \to N_1 \otimes F_0 \to N_1 \otimes N_2 \to 0 \,.$$

Since by construction $F_0$ and $F_1$ are already [[projective modules]] themselves this collapses to an exact sequence

$$0 \to Tor_1(N_1, N_2) \hookrightarrow N_1 \otimes F_1 \to N_1 \otimes F_0 \to N_1 \otimes N_2 \to 0 \,.$$

To the last three terms we apply the natural [[braided monoidal category|symmetric braiding]] [[isomorphism]] in $(R Mod, \otimes_R)$ to get

$$\array{ 0 &\to& Tor_1(N_1, N_2) &\hookrightarrow& N_1 \otimes F_1 &\to& N_1 \otimes F_0 &\to& N_1 \otimes N_2 &\to& 0 \\ && \downarrow && \downarrow^{\mathrlap{\simeq}} && \downarrow^{\mathrlap{\simeq}} && \downarrow^{\mathrlap{\simeq}} && \\ 0 &\to& Tor_1(N_2, N_1) &\hookrightarrow& F_1 \otimes N_1 &\to& F_0 \otimes N_1 &\to& N_2 \otimes N_1 &\to& 0 } \,.$$

This exhibits a morphism $Tor_1(N_1,N_2) \to Tor_1(N_2, N_1)$ as the morphism induced on [[kernels]] from an isomorphism between two morphisms. Hence this is itself an isomorphism. (This is just by the [[universal property]] of the [[kernel]], but one may also think of it as a simple application of the the [[four lemma]]/[[five lemma]].)

Localization

(…)

For instance (Weibel, cor. 3.2.13).

Related concepts

• [[Ext]]

• [[Cotor]]

• [[flat resolution lemma]]

• [[universal coefficient theorem]]

References

Standard textbook accounts include the following:

• [[Charles Weibel]], [[An Introduction to Homological Algebra]], Cambridge Studies in Adv. Math. 38, CUP 1994

• [[Henri Cartan]], [[Samuel Eilenberg]], Homological algebra, Princeton Univ. Press 1956.

• M. Kashiwara and P. Schapira, [[Categories and Sheaves]], Springer (2000)

• S. I . Gelfand, Yu. I. Manin, Methods of homological algebra

Lecture notes include

• Daniel Murfet, Tor (pdf)

section 3 of

• [[Peter May]], Notes on Tor and Ext (pdf)

and specifically for [[symmetric smash product of spectra|symmetric]] [[model categories of spectra]]

• [[Anthony Elmendorf]], [[Igor Kriz]], [[Peter May]], section 7 of [[Modern foundations for stable homotopy theory]] (pdf)

Original articles include

• Patrick Keef, On the Tor functor and some classes of abelian groups, Pacific J. Math. Volume 132, Number 1 (1988), 63-84. (Euclid)

[[!redirects Tor-functor]] [[!redirects Tor functor]] [[!redirects Tor-functors]] [[!redirects Tor functors]]